Q = p(r + s)
Use the distributive property
Q = pr + ps
Q = p x r + p x s
Q = p x p + r x s
Q = p^2 + rs
Subtract rs from both sides
Q - rs = p^2
Square root both sides
sqrt Q - rs = p
Okay so this is very easy so basically count the value of each coin then subtract to get *gets a call* hello? *other person starts talking* I just want you to know that the answer is 4 *hangs up* *starts talking* that was weird anyways the answer is four give
Answer:
i need to know the question to answer ir
Step-by-step explanation:
Answer:
(1,2) is a solution to both equations
Step-by-step explanation:
To determine if (1,2) is a solution to both equations, substitute into the equation and see if it is true
2x+y =4
2(1) + 2 =4
2+2 =4
4=4
true
y =3x-1
2 = 3(1) -1
2 =3-1
2=2
true
Since both statements are true
(1,2) is a solution to both equations
Answer:
∡A =41°
~~~~~~~~~~~~
BC=21
~~~~~~~~~~~~~~
sin(24)/AC=sin(41)/21
AC=13
~~~~~~~~~~~~~~
sin(115)/AB=sin(41)/21
AB=29
Step-by-step explanation:
