the collision is elastic as the carts rebound off each other.
by conservation of momentum, the small mass will have a larger change in velocity.
so the ans is The small cart changes its velocity the most.
Answer:
Check attachment for better understanding
Explanation:
Given that
a= 0.75m
b=1.31m
c= 2.2m
Weight of pole is 26.90
Then, Fg = Weight = 26.90
Using Equilibrium of forces
ΣFy = 0
U — D — Fg = 0
U — D = Fg
U — D = 26.9
To calculate U,
We will take moment about point A.
ΣMa = 0
Let the clockwise moment be positive and anti-clockwise be negative
Fg(a+b) — U(a) = 0
26.9(1.31+0.75) —0.75U = 0
26.9(2.06) = 0.75U
0.75U = 55.414
U = 55.414/0.75
U = 73.89 N
To calculate D,
U — D = 26.9
73.89—D =26.9
73.89—26.9 = D
D = 46.99N
Because energy is wasted either in the form of heat energy or something else (like friction)
Answer:

Explanation:
given,
total deflection = 4.12 cm
Electric field = 1.1 ×10³ V/m
plate length = 6 cm
distance between them = 12 cm
using formula

q = 1.6 × 10⁻¹⁹ C
m = 9.11 x 10⁻³¹ kg
d = 0.06 m
L = 0.12 m

v_0 = 6496355.63 m/s



