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professor190 [17]
3 years ago
8

Marta, Cato, and Juan plan a skit to illustrate one of the methods of charging. Marta and Cato are walking together. Each has on

e flower and one box of candy. Juan offers Cato a huge bouquet of flowers, but Cato can’t take it because his hands are full. Cato hands his flower to Marta and then turns to Juan to take the bouquet. Marta walks away in one direction with two flowers and one box of candy. Juan keeps the bouquet and walks away in the other direction. Cato looks sad standing alone with only a box of candy.
How does the skit model a method of charging?

A) It models induction because an electron (a flower) transfers from Cato to Marta through direct contact.

B) It models friction because an electron (a flower) transfers from Cato to Marta through direct contact.

C)It models friction because the offer of flowers represents a charged object that causes an electron (a flower) to transfer from one object to another.

D) It models induction because the offer of flowers represents a charged object that causes an electron (a flower) to transfer from one object to another.
Physics
1 answer:
sveta [45]3 years ago
8 0

Answer:

Option D.

Explanation:

Methods of charging:

1. By friction: when two materials of different electro-negativities rub against each, electrons transfer from one material to another.

2. By induction: When a charged body is brought near an uncharged body, the later gets polarized.

3. By conduction: when electrons from one body to another uncharged while contact, it is known as charging by conduction.

Here, a flower is analogous to an electron. A box of candy is positive charge. A bouquet of flowers is like a charged body which is brought near an uncharged body. It induces charge on ti it by causing it to transfer electron to another.

Thus, option D is correct.

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A woman is sitting at a bus stop when an ambulance with a siren wailing at 317 Hz approaches at 69 miles per hour (mph). Assume
xxMikexx [17]

Answer:

a) 30.84m/s

b) 348.32Hz

c) 32.34m/s

d) 289.69Hz

Explanation:

a) If 1 mile=1609,34m, and 1 hour=3600 seconds, then 69mph=69*1609.34m/3600s=30.84m/s

b) Based on Doppler effect:

/*I will take as positive direction the vector \vec r_{observer}-\vec r_{emiter} */

f_{observed}=(\frac{v_{sound}-v_{observed}}{v_{sound}-v_{emited}})f_{emited}

f_{observed}=(\frac{343m/s-0m/s}{343m/s-30.84m/s})317Hz=348.32Hz

c) 350Hz=(\frac{343m/s-0m/s}{343m/s-v_{ambulance}})317Hz, V_{ambulance}=343m/s-\frac{317Hz}{350Hz}.343m/s=32.34m/s

d) f_{observed}=(\frac{343m/s-0m/s}{343m/s+32.34m/s})317Hz=289.69Hz

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3 years ago
The friction force between a bag and the floor is 4 N. what is the net force acting on the bag? What is the acceleration of the
tester [92]
Well, if the bag is moving across the floor at a constant velocity. Then I would assume that the Fnet force is equal to 0, and thus the value of acceleration would also be equal to 0.
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2 years ago
An astronaut drops a rock from the top of a crater on the moon. When the rock is halfway down to the bottom of the crater, its s
Alexxx [7]

Answer: vf1/vf2= 1/ sqrt(2)

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if the rock travels H to the bottom we can calculate velocity:

vo=0m/s (drops the rock)  , yo=0

vf*vf= vo*vo+2g(y-yo)

when the rock is halfway  y = H/2 so:

vf1*vf1=2*g*H/2 so vf1 = sqrt(gH)

when the rock reach the bottom y=H so:

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2 years ago
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The greater the temperature, the greater the volume - this is Charles's law, said by Jacques Charles, a French inventor, scientist, and mathematician. 
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2 years ago
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An air-filled parallel-plate capacitor has plates of area 2.90 cm2 separated by 2.50 mm. The capacitor is connected to a(n) 18.0
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Complete question:

An air-filled parallel-plate capacitor has plates of area 2.90 cm2 separated by 2.50 mm. The capacitor is connected to a(n) 18.0 V battery. Find the value of its capacitance.

Answer:

The value of its capacitance is 1.027 x 10⁻¹² F

Explanation:

Given;

area of the plate, A = 2.9 cm² = 2.9 x 10⁻⁴ m²

separation distance of the plates, d = 2.5 mm = 2.5 x 10⁻³ m

voltage of the battery, V = 18 V

The value of its capacitance is calculated as;

C = \frac{k\epsilon_0A}{d} \\\\C = \frac{(1)(8.85\times 10^{-12})(2.9 \times 10^{-4})}{2.5 \times 10^{-3}} \\\\C = 1.027 \times 10^{-12} \ F

Therefore, the value of its capacitance is 1.027 x 10⁻¹² F

8 0
2 years ago
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