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professor190 [17]
3 years ago
8

Marta, Cato, and Juan plan a skit to illustrate one of the methods of charging. Marta and Cato are walking together. Each has on

e flower and one box of candy. Juan offers Cato a huge bouquet of flowers, but Cato can’t take it because his hands are full. Cato hands his flower to Marta and then turns to Juan to take the bouquet. Marta walks away in one direction with two flowers and one box of candy. Juan keeps the bouquet and walks away in the other direction. Cato looks sad standing alone with only a box of candy.
How does the skit model a method of charging?

A) It models induction because an electron (a flower) transfers from Cato to Marta through direct contact.

B) It models friction because an electron (a flower) transfers from Cato to Marta through direct contact.

C)It models friction because the offer of flowers represents a charged object that causes an electron (a flower) to transfer from one object to another.

D) It models induction because the offer of flowers represents a charged object that causes an electron (a flower) to transfer from one object to another.
Physics
1 answer:
sveta [45]3 years ago
8 0

Answer:

Option D.

Explanation:

Methods of charging:

1. By friction: when two materials of different electro-negativities rub against each, electrons transfer from one material to another.

2. By induction: When a charged body is brought near an uncharged body, the later gets polarized.

3. By conduction: when electrons from one body to another uncharged while contact, it is known as charging by conduction.

Here, a flower is analogous to an electron. A box of candy is positive charge. A bouquet of flowers is like a charged body which is brought near an uncharged body. It induces charge on ti it by causing it to transfer electron to another.

Thus, option D is correct.

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Answer:

Explanation:

mg = kx

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k = 0.40(9.8)/0.030

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You and a partner sit on the floor and stretch out a coiled spring to a length of 7.2 meters. You shake the coil so you
vekshin1

Answer:

Approximately 5.9\; {\rm m\cdot s^{-1}} (assuming that the partner is holding the other end of the coil stationary.)

Explanation:

In a standing wave, an antinode is a point that moves with maximal amplitude, while a node is a point that does not move at all. There is an antinode between every two adjacent nodes. Likewise, there is a node between every two adjacent antinodes.

The side of the spring that is being shaken moving with maximal amplitude. Hence, that point on this spring would also be an antinode. In contrast, the side of the spring that is held still (does not move at all) would be a node.

There would be a node between:

  • the antinode at the end of the spring that is being shaken, and
  • the antinode between the two ends of this spring.

Overall, the nodes and antinodes on this spring would be:

  • node at the end that is being held still,
  • antinode (as mentioned in the question),
  • node (inferred, not mentioned in the question), and
  • antinode at the end that is being shaken.

The distance between two adjacent nodes is equal to one-half (that is, (1/2)) the wavelength of the wave. The distance between a node and an adjacent antinode is one-quarter (that is, (1/4)) of the wavelength of the wave.

Thus, if the wavelength of the wave in this question is \lambda, the length of this spring would be:

\displaystyle \frac{1}{2}\, \lambda + \frac{1}{4}\, \lambda = \frac{3}{4}\, \lambda.

The question states that the length of this coiled spring is 7.2\; {\rm m}. In other words, (3/4) \, \lambda = 7.2\; {\rm m}. The wavelength of this wave would be (7.2\; {\rm m}) / (3/4) = 9.6\; {\rm m}.

The frequency f of this wave is the number of cycles in unit time:

\begin{aligned} f &= \frac{10}{16.3\; {\rm s}} \approx 0.613\; {\rm s^{-1}}\end{aligned}.

Hence, the speed v of this wave would be:

\begin{aligned} v &= \lambda\, f \\ &=9.6\; {\rm m} \times 0.613\; {\rm s^{-1}} \\ &\approx 5.9\; {\rm m \cdot s^{-1}}\end{aligned}.

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