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enot [183]
3 years ago
11

What type of nuclear radiation is emitted when carbon-14 decays

Physics
1 answer:
dalvyx [7]3 years ago
6 0

Answer:

Beta radiation

Explanation:

Beta radiation is a radioactive phenomenon of nuclear decay in which an unstable atom or isotop, by transforming a neutron into a proton, or by transforming a proton into a neutron, becomes stable. For example, the decay of carbon 14 produces beta radiation.

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A sailboat travels a distance of 600 m in 40 seconds. What speed is it going?
Gekata [30.6K]

Answer:

15 miles /seconds

Explanation:

Distance = 600m

Time = 40 seconds

Speed=?

speed =  \frac{distance}{time}  \\ speed =  \frac{600}{40}

Simplify

\frac{600}{40}  =  \frac{60}{4}  \\  = 15

7 0
3 years ago
Realiza la siguiente conversión de unidades: 340 N a Kgf
OleMash [197]

Answer:

The answer is 34.67 kilograms force

3 0
3 years ago
The maximum value of magnetic in an electric field 3.2 *10^4​
Svetradugi [14.3K]

Answer:

the answer is 12 because if your magnetic value and Electric field is 3.2 the answer will be 12

6 0
3 years ago
How can the IMA of a first- class lever be increased?
Dimas [21]
IMA = Ideal Mechanical Advantage

First class lever = > F1 * x2 = F2 * x1

Where F1 is the force applied to beat F2. The distance from F1 and the pivot is x1 and the distance from F2 and the pivot is x2

=> F1/F2 = x1 /x2

IMA = F1/F2 = x1/x2

Now you can see the effects of changing F1, F2, x1 and x2.

If you decrease the lengt X1 between the applied effort (F1) and the pivot,  IMA decreases.

If you increase the length X1 between the applied effort (F1) and the pivot, IMA increases.

If you decrease the applied effort (F1) and increase the distance between it and the pivot (X1) the new IMA may incrase or decrase depending on the ratio of the changes.

If you decrease the applied effort (F1) and decrease the distance between it and the pivot  (X1) IMA will decrease.

Answer: Increase the length between the applied effort and the pivot.
4 0
3 years ago
Read 2 more answers
A horizontal spring with spring constant 950 N/m is attached to a wall. An athlete presses against the free end of the spring, c
OLga [1]

Answer:

66.5N

Explanation:

F = kx

Where F = force

K = spring constant

x = compression

Given

K = 950N/m

x = 7.0cm

F = ?

First convert the compression to meters .

7.0cm = 7.0 x 0.01

= 0.07 meters

Therefore

F = 950 x 0.07

= 66.5N

4 0
3 years ago
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