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sweet-ann [11.9K]
3 years ago
5

Hw2-2 - show all your work, including the equation, express all answers in base units, (m, m/s, m/s2), unless stated otherwise i

n problem. a sprinter accelerates from rest to 10.5 m/s in 1.35 sec. what is her acceleration . . . in m/s2 km/hr2 a certain drag racer can accelerate from 0 to 60.0 km/hr in 5.4 sec. what is its acceleration in m/s2? how far, in meters, will it travel during this acceleration? how much time would it take to go 0.25 km if it could accelerate at this rate the entire time? an automobile can increase its speed uniformly from 25.0 to 55.0 km/h in 30.0 seconds. a bicycle rider uniformly speeds up to 30.0 km/h from rest in 0.5 min. calculate their accelerations. a rocket rises from rest with constant acceleration to an altitude of 85.0 km, at this point it has a speed of 2.8 km/s what is the acceleration of the rocket? how long does the ascent take?
Physics
1 answer:
Papessa [141]3 years ago
4 0
The useful equations here are derived equations for rectilinear motion at constant acceleration:

a = (v - v₀)/t
2ax = v² - v₀²
x = v₀t + 0.5at²

1.  Since it starts from rest, v₀ = 0. Then, v = <span>10.5 m/s and t=1.35 s
     a = (10.5 - 0)/1.35 = 7.78 m/s</span>²
     a = 7.78 m/s²*(1 km/1000 m)*(3,600 s/ 1 h)² = 100,828.8 km/h²

2. v₀ = 0; v = 60 km/h; t=5.4 s 
    a = [60 km/h*(1000 m/1km)*(1 h/3600 s) - 0]/5.4 s = 3.09 m/s²

3. Using the acceleration and velocities in #2, we can determine the distance     by the formula: 2ax = v² - v₀²
    2(3.09 m/s²)x = [60 km/h*(1000 m/1km)*(1 h/3600 s)]² - (0 m/s)²
    Solving for x,
    x = 44.95 m

4. Using acceleration in #2 and v₀ = 0, the time would be
    x = v₀t + 0.5at²
    0.25 km * 1,000 m/1 km = (0)(t) + (0.5)(3.09 m/s²)(t²)
    Solving for t,
    t = 12.72 seconds

5. Acceleration of automobile:
   a = [(55 km/h - 25 km/h)*(1,000 m/1 km)*(1 h/3,600 s)]/30 s
   a = 0.278 m/s²
<span>
   </span>Acceleration of bicycle:
   a = [(30 km/h - 0 km/h)*(1,000 m/1 km)*(1 h/3,600 s)]/(0.5 min * 60 s/1 min)
   a = 0.278 m/s²
<span>
6. x = 85 km or 85,000 m; v</span>₀ = 0 m/s; v = 2,800 m/s
    2ax = v² - v₀²
    2a(85,000 m) = (2,800 m/s)² - 0²
    a = 46.12 m/s²

7. Using the data given and acceleration in #6,
   x = v₀t + 0.5at²
   85,000 m = 0*t + 0.5(46.12 m/s²)(t²)
   Solving for t,
   t = 60.71 seconds
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Physical Properties of Sodium

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Home Periodic table Elements Sodium

Sodium - Na

Chemical properties of sodium - Health effects of sodium - Environmental effects of sodium

Atomic number

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8 0
2 years ago
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3 years ago
Liam throws a water balloon horizontally at 8.2 m/s out of a window 18 m from the ground.
Alecsey [184]

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h = \frac{1}{2} gt^2

here we know that

h = 18 m

g = 9.8 m/s^2

now by the above formula

18 = \frac{1}{2}*9.8* t^2

18 = 4.9 t^2

t = 1.92 s

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5 0
3 years ago
gas has a volume of 185 ml and pressure of 310 mm hg. The desiered volume is 74.0 ml. What is the required new pressure
Mamont248 [21]

Answer:

The required new pressure is 775 mm hg.

Explanation:

We are given that gas has a volume of 185 ml and a pressure of 310 mm hg. The desired volume is 74.0 ml.

We have to find the required new pressure.

Let the required new pressure be '\text{P}_2'.

As we know that Boyle's law formula states that;

                    P_1 \times V_1 = P_2 \times V_2

where, P_1 = original pressure of gas in the container = 310 mm hg

           P_2 = required new pressure

            V_1 = volume of gas in the container = 185 ml

            V_2 = desired new volume of the gas = 74 ml

So,  P_2 = \frac{P_1 \times V_1}{V_2}  

       P_2 = \frac{310 \times 185}{74}

            =  775 mm hg

Hence, the required new pressure is 775 mm hg.

7 0
3 years ago
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