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Levart [38]
3 years ago
5

What is 4/5 of 15. Pls tell MAEEE!!!

Mathematics
1 answer:
kirill115 [55]3 years ago
6 0

Answer:

12

Step-by-step explanation:

of is a another word for multiplying or multiplication

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I really need help!!! It would mean a lot if someone could help me.
Rudiy27

The y answers would be 11, 8, 5, 2, -1.

To find these parts of the table, we simply put the x value in for x and solve for y. The first two are done for you below.

WHEN x = -2

y = -3x + 5

y = -3(-2) + 5

y = 6 + 5

y = 11

WHEN x = -1

y = -3x + 5

y = -3(-1) + 5

y = 3 + 5

y = 8

4 0
3 years ago
Read 2 more answers
Find the values of m and b that make the following function differentiable.
KengaRu [80]

f(x)=\begin{cases}x^2&\text{for }x\le2\\mx+b&\text{for }x>2\end{cases}

In order to be differentiable everywhere, f must first be continuous everywhere, which means the limits from either side as x\to2 must be the same and equal to f(2). By definition, f(2)=2^2=4, and

\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2}x^2=4

\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2}(mx+b)=2m+b

so we need to have 4m+b=4.

For f to be differentiable at x=2, the derivative needs to be continuous at x=2, i.e.

\displaystyle\lim_{x\to2^-}f'(x)=\lim_{x\to2^+}f'(x)

We then need to have

\displaystyle\lim_{x\to2}2x=\lim_{x\to2}m\implies\boxed{m=4}

Then

2m+b=4\implies\boxed{b=-4}

7 0
3 years ago
What is the domain and range of the function graphed??
PIT_PIT [208]
Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis
5 0
3 years ago
What is the center and radius of the circle with the equation x2 + y2 = 42
MakcuM [25]
The sender is seven hundred ajdhfkandhf
8 0
3 years ago
What is 12 divided by 2/3<br><br><br><br> What is 2/3 divided by 12
Alex777 [14]
12 divided by 2/3 = 18
2/3 divided by 12 = 0.5
8 0
3 years ago
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