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sertanlavr [38]
3 years ago
13

(-6+i)(8-3i)(-1+i) simplify

Mathematics
1 answer:
rewona [7]3 years ago
5 0
Hope this helps. If you have any further question ask in comments.

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Which function has no horizontal asymptote? F (x) = StartFraction 2 x minus 1 Over 3 x squared EndFraction f (x) = StartFraction
yanalaym [24]

Answer:

f(x)=\frac{2x^2}{3x-1}

Step-by-step explanation:

The function  f(x)=\frac{2x-1}{3x} has a horizontal asymptote which is y=\frac{2}{3}

The function  f(x)=\frac{x-1}{3x} has a horizontal asymptote which is y=\frac{1}{3}

The function  f(x)=\frac{2x^2}{3x-1} has no horizontal asymptote  because the numerator has a degree which is higher than the degree of the denominator,

The function  f(x)=\frac{3x^2}{x^2-1} has a horizontal asymptote which is y=3

3 0
3 years ago
Read 2 more answers
Find the value of x. <br> A. 2 <br> B. 3 <br> C. 4 <br> D. 5
masya89 [10]
The correct answer is three.
7 0
3 years ago
Witch expression is the factorization of x2+10x+21
Alenkasestr [34]

Answer:

x^2 +x(7+3) +21

x^2 +7x + 3x +21

x(x+7) +3(x+7)

(x+7) (x+3)

6 0
3 years ago
X+y+z =4
cestrela7 [59]
<span><span> <span>Akar akar persamaan kuadrat 2x² - 3x -1 = 0 adalah x1 dan x2. Persamaan kuadrat baru yang akar akarnya satu lebih kecil dari dua kali akar akar persamaan kuadrat di atas adalah ........</span></span><span><span><span>A.x² - x - 4 = 0</span><span>B.x² + 5x - 4 = 0</span><span>C.x² - x + 4 = 0</span></span><span><span>D.x² + x + 4 = 0</span><span>E.x² - 5x - 4 = 0</span></span></span><span>Jawaban : A
Penyelesaian : 
Akar-akar persamaan lama :  x1 dan x2
                                             
Akar-akar persamaan baru :  xA dan xB
                                             xA = 2x1 - 1
                                             xB = 2x2 - 1
                                             xA + xB  = (2x1 - 1) + (2x2 - 1)
                                                           = 2 (x1 + x2) - 2
                                                           = 2 () - 2
                                                           = 3 - 2
                                              xA + xB = 1
    
                                              xA . xB = (2x1 - 1) (2x2 - 1)
                                                          = 4 x1.x2 - 2(x1 + x2) + 1
                                                          = 4.(-) - 2() + 1
                                                          = -2 - 3 + 1
                                              xA . xB = -4
    
Jadi persamaan kuadrat baru : x² - (xA + xB)x + xA . xB = 0
                                              x² - x - 4 = 0

</span></span>
4 0
4 years ago
What is the product?
RSB [31]

Answer:

15a^5b^15

Step-by-step explanation:

you multiply 5 and 3 to get 15, and then when you are multiplying exponents of variables, you actually add them, so a^2 times a^3 is actually a^5, and b^7 times b^8 is b^15. Because these are all multiplied together, you get the answer of 15a^5b^15.

4 0
3 years ago
Read 2 more answers
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