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maw [93]
4 years ago
8

What is the significance of the mean of a probability​ distribution?

Mathematics
1 answer:
VikaD [51]4 years ago
4 0

Answer:

Significance of the mean of a probability​ distribution.          

Step-by-step explanation:

  • The mean of a probability distribution is the arithmetic average value of a random variable having that distribution.
  • For a discrete probability distribution, the mean is given by, \sum x_iP(x_i), where P(x) is the probabiliy mass function.
  • For a continuous probability distribution, the mean s given by, E(x) = \int x_if(x_i), where f(x) is the probability density function.
  • Mean is a measure of central location of a random variable.
  • It is the weighted average of the values that X can take, with weights given by the probability density function.
  • The mean is known as  expected value or expectation of X.
  • An important consequence of this is that the mean of any symmetric random variable (continuous or discrete) is always on the axis of symmetry of the distribution.
  • For a continuous random variable, the mean is always on the axis of symmetry of the probability density function.
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Part 23. NO LINKS!! What is the area of this figure?​
nalin [4]

Answer:

  • 117 in²

Step-by-step explanation:

<u>Here are the steps on how we will solve this problem.</u>

  • Step 1: Divide the shape into squares and rectangles.
  • Step 2: Find the area of all squares and rectangles
  • Step 3: Sum up all the areas to get your final answer.

Now, let's follow the steps. Please consider looking at the picture I uploaded. Looking at the picture, we can tell that the area is 70 + 32 + 15. Now, let's solve.

  • 70 + 32 + 15
  • => 102 + 15
  • => 117 in²

Hence, the area of the shape is 117 in².

5 0
3 years ago
Read 2 more answers
I don't understand at all please help.
snow_tiger [21]
You have to use the different exponent rules you can search them up to see what you have to do
4 0
4 years ago
y=c1e^x+c2e^−x is a two-parameter family of solutions of the second order differential equation y′′−y=0. Find a solution of the
vagabundo [1.1K]

The general form of a solution of the differential equation is already provided for us:

y(x) = c_1 \textrm{e}^x + c_2\textrm{e}^{-x},

where c_1, c_2 \in \mathbb{R}. We now want to find a solution y such that y(-1)=3 and y'(-1)=-3. Therefore, all we need to do is find the constants c_1 and c_2 that satisfy the initial conditions. For the first condition, we have:y(-1)=3 \iff c_1 \textrm{e}^{-1} + c_2 \textrm{e}^{-(-1)} = 3 \iff c_1\textrm{e}^{-1} + c_2\textrm{e} = 3.

For the second condition, we need to find the derivative y' first. In this case, we have:

y'(x) = \left(c_1\textrm{e}^x + c_2\textrm{e}^{-x}\right)' = c_1\textrm{e}^x - c_2\textrm{e}^{-x}.

Therefore:

y'(-1) = -3 \iff c_1\textrm{e}^{-1} - c_2\textrm{e}^{-(-1)} = -3 \iff c_1\textrm{e}^{-1} - c_2\textrm{e} = -3.

This means that we must solve the following system of equations:

\begin{cases}c_1\textrm{e}^{-1} + c_2\textrm{e} = 3 \\ c_1\textrm{e}^{-1} - c_2\textrm{e} = -3\end{cases}.

If we add the equations above, we get:

\left(c_1\textrm{e}^{-1} + c_2\textrm{e}\right) + \left(c_1\textrm{e}^{-1} - c_2\textrm{e}  \right) = 3-3 \iff 2c_1\textrm{e}^{-1} = 0 \iff c_1 = 0.

If we now substitute c_1 = 0 into either of the equations in the system, we get:

c_2 \textrm{e} = 3 \iff c_2 = \dfrac{3}{\textrm{e}} = 3\textrm{e}^{-1.}

This means that the solution obeying the initial conditions is:

\boxed{y(x) = 3\textrm{e}^{-1} \times \textrm{e}^{-x} = 3\textrm{e}^{-x-1}}.

Indeed, we can see that:

y(-1) = 3\textrm{e}^{-(-1) -1} = 3\textrm{e}^{1-1} = 3\textrm{e}^0 = 3

y'(x) =-3\textrm{e}^{-x-1} \implies y'(-1) = -3\textrm{e}^{-(-1)-1} = -3\textrm{e}^{1-1} = -3\textrm{e}^0 = -3,

which do correspond to the desired initial conditions.

3 0
3 years ago
A washer and a dryer cost $713 combined. The washer costs $37 less than the dryer. What is the cost of the dryer
77julia77 [94]

Answer:

375

Step-by-step explanation:

713 - 37 = 676

676 divided by 2 = 338

That would be the washer but we need to add the 37 again for the dryer

338 + 37 = 375

3 0
3 years ago
there are 10 less trumpet players than saxophone players. The number if saxophone players is 3 times the number of trumpet playe
cluponka [151]

<em>Answer: There are 5 trumpet players and 15 saxophone player</em>


<em>Step-by-step explanation: Let a be the number of trumpet players </em>

<em>Let b be the number of saxophone players </em>

<em>--------------------- </em>

<em>(1) a = b-10 </em>

<em>(2) b =3a </em>

<em>---------------- </em>

<em>Substitute  </em>

<em>(2) into (1) </em>

<em>(1) a =3a-10 </em>

<em>(1) 2a =10  </em>

<em> </em>

<em> (1) a = 5and </em>

<em>(2) b = 3(5)(2)  </em>

<em>b =  15 </em>

<em>------------------ </em>

<em>There are 5 trumpet players and 15 saxophone player</em>


5 0
3 years ago
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