X=width of the lake
y=length of the lake.
we set out this system of equiations
x*y=9/20
x=y/5
we solve by sustitution method
(y/5)*y=9/20
y²/5=9/20
y²=(5*9)/ 20
y²=2.25
y=√2.25=1.5
x=y/5
x=1.5/5=0.3
Solution:
width of the lake=0.3 miles
lenght of the lake=1.5 miles
Answer:
x>0
Step-by-step explanation:
Answer:
0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:
The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min.
This means that
If one such class is randomly selected, find the probability that the class length is between 51.5 and 51.7 min.
0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.
The value of the truck initially, Ao is
83000
1-0.16=0.84
1-0.26=0.74
After one year the value
Y=83,000×(0.84)=69,720
Y=83,000×(0.74)=61,420
When you compare the results you will see that the graph would fall at a faster rate to the right because the depreciation rate of 26% is higher than the depreciation rate of 16%
Hope it helps