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GalinKa [24]
3 years ago
10

A $30 pair of jeans is on sale for $15. What is the percent of change for the pair of jeans?

Mathematics
1 answer:
tester [92]3 years ago
8 0

Answer:

50%

Step-by-step explanation:

All we need to do is find out what percent 15 is compared to 30. So think of 30 as "100%" in this case. We know it's on sale and selling for $15 so all we need to do is figure out what $15 is compared to $30.

30 ÷ 15 = 15.

Luckily in this case 15 is half of 30. So half of "100" would be 50. 50%.

50% is your answer.

<u>Hope this helps and have a nice day!</u>

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Scores on a college entrance exam are normally distributed with a mean of 550 and a standard deviation of 100. Find the value th
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Answer:

The value that represents the 90th percentile of scores is 678.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 550, \sigma = 100

Find the value that represents the 90th percentile of scores.

This is the value of X when Z has a pvalue of 0.9. So X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 550}{100}

X - 550 = 100*1.28

X = 678

The value that represents the 90th percentile of scores is 678.

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