2 will replace each x on the right
3•(2^3) - 4•(2^2) + 2 -1
3•8 - 4•4 + 1
24 - 16 + 1
8+1
9
D
there is always a 1 infront of a variable but since x2 has the largest degree it gives it priority over the others so what ever numbe in front of it is the leading coefficient
Step-by-step explanation:
<u>Formula</u><u> </u><u>U</u><u>s</u><u>e</u><u>d</u>
<u>By distance formula,</u>
- d (A,B)=√[(x₁ - x₂)² + (y₁ - y₂)²]




RS+ST= RT
(7Y+3)+(2Y+9)= 14Y-8
9Y+12=14Y-8
5Y=20
Y=4
Answer:
31.4 in³
Step-by-step explanation:
The box is just big enough to hold the 3 balls, so it must have a length 6 times the radius of each ball, a width 2 times the radius, and a height 2 times the radius.
The volume of the box is:
V = (6r)(2r)(2r)
V = 24r³
The volume of the 3 balls is:
V = 3 (4/3 π r³)
V = 4πr³
So the volume of the air is:
V = 24r³ − 4πr³
V = (24 − 4π) r³
Since r = 1.4 inches:
V = (24 − 4π) (1.4 in)³
V ≈ 31.4 in³