Ask question

Ask question

All categories

3 years ago

13

Which Universal Life option has a gradually increasing cash value and a level death benefit?

1 answer:

Damm [24]3 years ago

3 0

Answer:The universal life insurance option A

Step-by-step explanation:

You might be interested in

Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and

tia_tia [17]

$p=501\cdot503\cdot\cdots\cdot597$

$q=\underbrace{501\cdot503\cdot\cdots\cdot597}_p\cdot599\cdot601$

So we have $q=359,999p$ . Then

$\dfrac1p+\dfrac1q=\dfrac{359,999}{359,999p}+\dfrac1q=\dfrac{359,999+1}q=\dfrac{360,000}q$

and the answer is D.

4 0

3 years ago

Does anyone know how to calculate this

stich3 [128]

Answer:

no not me sorry I wish I could help.

5 0

2 years ago

Which of the following polynomial functions is graphed below? OA. f(x) = (x - 2) ^ 2 * (x + 3) * (x - 1) O B. f(x) = (x + 2) ^ 2

laila [671]

The function of the polynomial is (b) $f(x) = (x + 2) ^ 2 * (x - 3) * (x + 1)$

From the graph, we have the following highlights

The graph crosses the x-axis at x = -1 and x = 3
The graph touches the x-axis at x = -2

The above highlights mean that:

The function has a multiplicity of 1 at x = -1 and x = 3
The function has a multiplicity of 2 at x = -2

So, the function of the polynomial is:

$f(x) =a(x + 2)^2(x + 1)(x - 3)$

Assume a = 1.

So, we have:

$f(x) =1(x + 2)^2(x + 1)(x - 3)$

Multiply

$f(x) =(x + 2)^2(x + 1)(x - 3)$

Hence, the function of the polynomial is (b) $f(x) = (x + 2) ^ 2 * (x - 3) * (x + 1)$

Read more about polynomial graphs at:

brainly.com/question/8878887

8 0

3 years ago

F(h) = -2(h - 4)2 + 22.

Ivenika [448]

Here’s what I found that can help you step by step

5 0

3 years ago

A cone has a radius of 5 ft and a height of 15 ft. It is empty and is being filled with water at a constant rate of 15 15 ft 3 f

kvasek [131]

Answer:

$\frac{dr}{dt}=0.11062ft/sec$

Step-by-step explanation:

From the question we are told that:

Radius $r=5ft$

Height $H=15ft$

Rate $R=15ft/3sec =5ft/s$

Surface Radius $R_{surf}=2.2ft$

Generally the equation for Volume is mathematically given by

$V=\frac{1}{3}\pi*r^2h$

Since radius to height ratio gives

$\frac{r}{h}=\frac{5}{15}$

$\frac{r}{h}=\frac{1}{3}$

$h=3r$

Therefore

$V=\frac{1}{3}\pi*r^2(3r)$

$V=\pi r^3$

Generally the equation for Change of Volume is mathematically given by

$\frac{dv}{dt}=\pi \frac{d}{dt}(r^3)$

$\frac{dv}{dt}=\pi 3*r^2 \frac{dr}{dt}$

$\frac{dv}{dt}=\pi 3*(2.2)^2 \frac{dr}{dt}$

$\frac{dr}{dt}=\frac{5}{45.62}$

$\frac{dr}{dt}=0.11062ft/sec$

3 0

3 years ago