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guajiro [1.7K]
3 years ago
11

The temperature at 7:00 a.m. was –5°F. By 4:00 p.m., the temperature had risen 9 degrees and by 10:00 p.m. the temperature dropp

ed 11 degrees. What was the temperature at 10:00 pm
Mathematics
1 answer:
ivanzaharov [21]3 years ago
5 0

Answer:

-7 degrees

Step-by-step explanation:

-5+9-11=-7

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Suppose f is a linear function with slope 3.7 and that f(4)=-7. What value of x gives f(x)=0?
dedylja [7]

Answer:

x=5.9

Step-by-step explanation:

we know that

The linear function in slope intercept form is equal to

f(x)=mx+b

we have

m=3.7\\point (4,-7)

substitute and solve for b

-7=(3.7)(4)+b

-7=14.8+b

b=-21.8

The linear function is

f(x)=3.7x-21.8

For f(x)=0

substitute and solve for x

0=3.7x-21.8

3.7x=21.8

x=21.8/3.7

x=5.9

7 0
3 years ago
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ch4aika [34]

Answer:

it is the 50th tearm

Step-by-step explanation:

I just added '2' to '1' 50 times in a sense and got 99

3 0
3 years ago
Evaluate - x2 + y2 where x= -1 and y=3
o-na [289]

Answer:

8

Step-by-step explanation:

-(-1)^2+(3)^2=-1+9\\=8

3 0
3 years ago
Identifying the values a, b, and c is the first step in using the Quadratic Formula to find solution(s) to a quadratic equation.
lesya692 [45]

The values of a, b, and c in given quadratic equation are:

a = 6 and b = -9 and c = 7

<em><u>Solution:</u></em>

Given quadratic equation is:

-6x^2 = -9x + 7

Let us first convert the given quadratic equation to standard form

The standard form is ax^2+bx+c=0 with a, b, and c being constants, or numerical coefficients, and x is an unknown variable

-6x^2 = -9x + 7\\\\-6x^2+9x-7=0\\\\6x^2-9x+7=0

Now we have to find the values of a, b, c

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Thus comparing 6x^2-9x+7=0 with standard form of quadratic equation a x^{2}+b x+c=0

a = 6

b = -9

c = 7

Thus values of a, b, and c are found

3 0
3 years ago
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Leto [7]
I think it is 40 percent of1,000
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3 years ago
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