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3 years ago

The replica of the Empire State Building with its antenna spire in Las Vegas is

Mathematics

1 answer:

postnew [5]3 years ago

3 0

Answer: $\frac{485}{ 1,454}$

Step-by-step explanation:

For this exercuse you need to analize the information provided. You know that:

1) The height of the replica of the Empire State Building with its antenna spire in Las Vegas is 485 feet.

2) The height of the real Empire State building is 1,454 feet.

Finally, in order to find the ratio of height of the replica to the height of the real Empire State building, its necessary to divide the height of the replica of the Empire State Building by the height of the real Empire State building.

Therefore, trough this procedure you get that the ratio of height of the replica to the height of the real Empire State building is:

$ratio=\frac{heigth_{ replica}}{heigth_{real}}=\frac{485}{ 1,454}$

(This fraction cannot be reduced)

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Please help me with precalculus??<br>linear and angular speed

Anit [1.1K]

13)

there are 2π radians in 1 revolution, and there are 60 seconds in 1 minute, so keeping that in mind, then,

$\bf \cfrac{4\underline{\pi} }{5~\underline{s}}\cdot \cfrac{rev}{2\underline{\pi} }\cdot \cfrac{60~\underline{s}}{min}\implies \cfrac{4\cdot 60~rev}{5\cdot 2~min}\implies \cfrac{240~rev}{10~min}\implies 24\frac{rev}{min}$

14)

$\bf \textit{linear velocity}\\\\
v=rw\quad 
\begin{cases}
r=radius\\
w=angular~speed\\
----------\\
v=32\frac{m}{sec}\\
w=100\frac{rev}{min}
\end{cases}\\\\
-------------------------------\\\\
\textit{let's convert \underline{w} to }\frac{radians}{sec}$

$\bf \cfrac{100~\underline{rev}}{\underline{min}}\cdot \cfrac{2\pi }{\underline{rev}}\cdot \cfrac{\underline{min}}{60~sec}\implies \cfrac{100\cdot 2\pi }{60~sec}\implies \cfrac{10\pi }{3~sec}\implies \cfrac{10\pi }{3}\frac{radians}{sec}\\\\
-------------------------------\\\\
v=rw\implies \cfrac{v}{w}=r\implies \cfrac{\frac{30~m}{sec}}{\frac{10\pi }{3~sec}}\implies r=\cfrac{30~m}{\underline{sec}}\cdot \cfrac{3~\underline{sec}}{10\pi }
\\\\\\
r=\cfrac{90}{10\pi }m$

15)

what is the radians per seconds "w" in revolutions per minute? just another conversion like in 13)

$\bf \cfrac{\underline{\pi} }{3~\underline{sec}}\cdot \cfrac{rev}{2\underline{\pi }}\cdot \cfrac{60~\underline{sec}}{min}\implies \cfrac{60 ~rev}{3\cdot 2 ~min}\implies \cfrac{60 ~rev}{6 ~min}\implies 10\frac{rev}{min}$

4 0

4 years ago

Suppose an investment account is opened with an initial deposit of $11,000 earning 7.2% interest. Round all answers to the neare

Bingel [31]

Answer:$800 to the nearest dollar

Step-by-step explanation:

To find this

7.2/100×$11000

=$792

To the nearest dollar

$800

8 0

3 years ago

This my test question I'm 100 bad at math 2b2+16b+49÷2b+4

krek1111 [17]

2b^2 + 81/2 b + 4

basically 2b^2 + 16b + 49/2 b + 4
= (2b^2) + 16b+49/2b) + (4)
= 2b^2 + 81/2 b + 4

5 0

3 years ago

Describe the slope of the line<br> Find the slope

Dmitry_Shevchenko [17]

Answer:

Question one: Zero slope
Question two: $m=\frac{0}{4}$

Step-by-step explanation:

Given the following questions:

<u>Question one:

</u>The following line is what you call a "zero slope." Zero slopes are lines that are neither decreasing or increasing and remain at a constant or just a straight line.

Question two:

Point A = (-2, -3) = (x1, y1)
Point B = (2, -3) = (x2, y2)

Using the formula for slope or rise over run we will solve and find the slope of this line.

$m=\frac{y2-y1}{x2-x1}$
$m=\frac{-3--3}{2--2} =\frac{0}{4}$
$m=\frac{0}{4}$

The slope of this line is "0/4."

Hope this helps.

8 0

2 years ago

Hhelp me pleaseeeeee

svetlana [45]

A. Area = ½b × h

= ½ × 16 × 9

= 72

B. Area = b × h

= 26 × 18

= 468

C. Area = a²

= 11²

= 121

D. Area = ½(a+b) × h

= ½(6+21) × 8

= 108

Hope this helps :)

Please consider marking my answer the brainliest!

4 0

3 years ago