Question

A right triangle is drawn on a coordinate plane. Two vertices of the triangle are points A(−2,4) and B(3,−2) . The third vertex of the triangle is point C, which lies in the third quadrant of the coordinate plane.
What is the distance from point A to point C?



Enter your answer in the box

Answer 1

As you can see in the image, point C must be (-2, -2), because it is the only point that will create a right triangle that is in the third quadrant.

To find the distance between point A and point C, just subtract the y-values.

$\sf 4-(-2)=\boxed{\sf 6}$