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pentagon [3]
4 years ago
12

A spinner with 10 equal-sized sections numbered 1 to 10 is spun once. What is the probability that the spinner will land on a nu

mber that is not a multiple of three?
Mathematics
2 answers:
deff fn [24]4 years ago
7 0
7/10
because 3, 6, 9
so 10-3=7
so you get 7/10 



mestny [16]4 years ago
7 0
The probability is 7 out of 10 or 70% beacuse there are three multiple of three in 10 nad those are 3, 6, and 9. If there are 10 equal sides and three of them are occupied with multiples of three, that means you have a 70% chance of landing on a number that is not a multiple of three.
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OverLord2011 [107]

Answer:

1) p1=0.83

2) p2=0.81

3) Option B

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5) s=0.03

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Step-by-step explanation:

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s=\sqrt{\frac{\bar{p}(1-\bar{p})}{n_1} +\frac{\bar{p}(1-\bar{p})}{n_2}} \\\\s=\sqrt{\frac{0.82*0.18}{311} +\frac{0.82*0.18}{363}} \\\\s=\sqrt{0.00047+0.00041} =\sqrt{0.00088}=0.03

6) The z-statistic can be calculated as:

z=\frac{p_1-p_2}{s}=\frac{0.83-0.81}{0.03}=\frac{0.02}{0.03}=0.67

7) The P-value for z=0.67 is P=0.50 (from the standard normal distribution table).

2P(Z>|z|)=0.50286

8) If the significance level is 0.01, the P-value is bigger than the significance level. The effect is not significanct. The null hypothesis is not rejected.

There is not enough evidence to say that both proportions are different.

A. Do not reject H0

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