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slava [35]
3 years ago
15

A11 if a3=5/16 and r=2

Mathematics
1 answer:
harina [27]3 years ago
3 0

Answer:

80

Step-by-step explanation:

The n th term of a geometric sequence is

a_{n} = a₁(r)^{n-1}

where a₁ is the first term and r the common ratio

We require to find a₁

Given

a₃ = \frac{5}{16}, then

a₁r² = \frac{5}{16}, that is

a₁ ×2² = \frac{5}{16} ( divide both sides by 4 )

a₁ = \frac{5}{64}, thus

a_{11} = \frac{5}{64} × 2^{10} = \frac{5}{64} × 1024 = 5 × 16 = 80

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