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Radda [10]
3 years ago
14

What is the quotient of (5x2 − 22x + 8) ÷ (x − 4)?

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
6 0
The answer should be near 41.5
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X - 35 > 15 i need answer IMEDIATLEY
SIZIF [17.4K]

I'm assuming you want us to solve this inequality for x, since the question wasn't too clear on that.

x - 35 > 15

Add 35 to both sides to remove the "-35" on the left side so we can isolate the x

x-35+35>15+35

x>50

The solution to this inequality is x>50. Let me know if you need any clarifications, thanks!

~ Padoru

6 0
3 years ago
Of the 27 players trying out for the school basketball team, 8 are more than 6 feet tall and 7 have good aim. What is the probab
Komok [63]
Of the 27 players trying out for the school basketball team, 8 are more than 6 feet tall and 7 have good aim. What is the probability that the coach would randomly pick a player over 6 feet tall or a player with a good aim? Assume that no players over 6 feet tall have good aim. A. 7/15 B. 6/15 C. 7/9 D. 5/9

The Answer Is

--------5/9--------
5 0
3 years ago
Which table contains only corresponding x - values and y - values where the value of y is 3 more than the quotient of x and 2?
melisa1 [442]

Fr like whats the answer choice

6 0
2 years ago
Read 2 more answers
Please answer this please
cluponka [151]

Step-by-step explanation:

<h3>1. x² + 4 = (x+2)² </h3>

<h3> : x² + 4 = x² + 4 (Yes)</h3>

<h3>2. (2x+6)²= 4(x+3)²</h3>

<h3> : 4x²+36 = 4x² + 36 ( Yes)</h3>

<h3>3. (x-3)(x-3)= (x-9)² (NO)</h3>

<h3>beacause , True statement is</h3><h3> (x+3)(x-3)= (x-9)²</h3>

<h3>4. x²-10x+25 = (x-5)(x+5) (No)</h3>

<h3> : x²-2x+y² = (a-b)(a+b) </h3>

<h3>Therefore, its not true statement!</h3>
4 0
3 years ago
Find the vertices and foci of the hyperbola with equation quantity x plus 5 squared divided by 36 minus the quantity of y plus 1
Sphinxa [80]

Answer:

Vertices: (1,-1), (-11, -1); Foci: (-15, -1), (5, -1)

Step-by-step explanation:

Center at (-5,-1) because of the plus 5 added to the x and the plus 1 added to the y.

a(squared)=36 which means a=6 and a=distance from center to vertices so add and subtract 6 from the x coordinate since this is a horizontal hyperbola, which is (1,-1), (-11,-1). From there you dont need to find the focus since there is only one option for this;

Vertices: (1,-1), (-11, -1); Foci: (-15, -1), (5, -1)

8 0
3 years ago
Read 2 more answers
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