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Kitty [74]
3 years ago
6

The difference between newtons first law of motion and newtons third law of motion

Physics
1 answer:
zmey [24]3 years ago
6 0

The difference is two laws of motion.
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A particular car engine operates between temperatures of 440°C (inside the cylinders of the engine) and 20°C (the temperature of
Step2247 [10]

One of the concepts to be used to solve this problem is that of thermal efficiency, that is, that coefficient or dimensionless ratio calculated as the ratio of the energy produced and the energy supplied to the machine.

From the temperature the value is given as

\eta = 1-\frac{T_L}{T_H}

Where,

T_L = Cold focus temperature

T_H = Hot spot temperature

Our values are given as,

T_L = 20\° C = (20+273) K = 293 K

T_H = 440\° C = (440+273) K = 713 K

Replacing we have,

\eta = 1-\frac{T_L}{T_H}

\eta = 1-\frac{293}{713}

\eta = 0.589

Therefore the maximum possible efficiency the car can have is 58.9%

4 0
3 years ago
Solids diffuse because the particles cannot move.
Nastasia [14]

Solids cannot diffuse.

4 0
3 years ago
Read 2 more answers
If measurements of gas are 75 L and 300 kIlopascals and then the gas is measured is second time and found to be 50 L, describe w
Ann [662]

Answer:

The pressure must have increased in the process

Explanation:

The State Equation for gasses reads: P*V=n*R*T

where P is the gas' pressure, V its volume, n the number of moles of gas,  R the gas constant and T the temperature in degrees Kelvin.

If the temperature of the gas doesn't change in the described process, the right hand side of the equation stays the same. If that is the case, given that when the Volume of the gas diminishes from 75 liters to 50 liters, then the pressure must have increased to keep that product "P * V" constant:

P_i*V_i=P_f*V_f\\75 *300=50*X\\X=\frac{75*300}{50} =450

So the pressure must have gone up to 450 kilopascals.

3 0
2 years ago
A cyclist has a constant speed of 12 m/s. What is the magnitude of the displacement of the cyclist after 18 seconds?
Katyanochek1 [597]

Answer:

216 m

Explanation:

Assuming a straight line:

Δx = vt

Δx = (12 m/s) (18 s)

Δx = 216 m

7 0
3 years ago
Which of the following statements is TRUE in regards to Signal #2?
Marina CMI [18]

Answer:

2) Signal #2 is a digital signal that transmits signals in segments/intervals.

Explanation:

Signals are form of information propagating from the source to a display unit for appropriate interpretation. It can be either in a digital or analogue form.

A digital signal is a definite signal which is discrete in time and amplitude. It is mostly in the form of codes obtained from set of values. Graphically it transmits in the form of 1 and 0, showing a point of maximum amplitude (1) and minimum amplitude (0).

Analog signal is continuous signal describing the variation of two variables with respect to time.

7 0
3 years ago
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