The wires that will have the least resistance is :
C. A short thick wire
in order to get the least resistence, you need the wire to be the lowest in length and the highest in Area
hope this helps
Answer:
Part A 2.88 A, PART B 28.82 mA PART C 0.288 mA
Explanation:
We have given angular frequency 
Voltage source has an amplitude of 24.5 V, So V= 24.5 volt
Part A
We have given inductance 
So inductive reactance 
So current 
Part B
We have given inductance 
So inductive reactance 
So current 
Part C
We have given inductance 
So inductive reactance 
So current 
Answer:
4000 J
Explanation:
W = F = 2000N , s = 20 m
Workdone = F × s = 200 × 20 = 4000J
Answer:

Explanation:
Take at look to the picture I attached you, using Kirchhoff's current law we get:

This is a separable first order differential equation, let's solve it step by step:
Express the equation this way:

integrate both sides, the left side will be integrated from an initial voltage v to a final voltage V, and the right side from an initial time 0 to a final time t:

Evaluating the integrals:

natural logarithm to both sides in order to isolate V:

Where the term RC is called time constant and is given by:
