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PSYCHO15rus [73]
3 years ago
8

You are running late for class and are still in the hallway when the bell rings. The tardy bell is right outside your classroom

door, and your teacher is standing directly beneath it. If you are running towards the bell when it rings, which of the following best describes what you hear? (DOK 1)
Question 8 options:

A. You hear a higher pitch than your teacher


B. You hear a lower pitch than your teacher


C. You hear a louder pitch than your teacher


D. You hear the same pitch as your teacher
Physics
1 answer:
Sphinxa [80]3 years ago
5 0

Answer:

C

Explanation:

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Circular coil 1 has N turns and circular coil 2 has 6N. Coil 1 has area A and coil 2 has area A/4. If Coil 1 has current i runni
solmaris [256]

Answer:

\frac{L_1}{L_2} =\frac{1}{3}

Explanation:

Recall that the formula for an inductance (L) for coil on N turns, are A and current I is given by:

L=\frac{\mu_0\,N^2\,A}{I}

Then, for the first coil we have;

L_1=\frac{\mu_0\,N^2\,A}{I}

and for coil 2 we have:

L_2=\frac{\mu_0\,(6\,N)^2\,(A/4)}{3\,I}

then, the quotient L1/L2 can be written as:

\frac{L_1}{L_2} =\frac{\mu_0\,N^2\,A\,3\,I}{\mu_0\,(6\,N)^2\,(A/4)\,I}=\frac{12}{36} =\frac{1}{3}

7 0
3 years ago
A cannonball is shot from the top of a 30
lyudmila [28]

Answer:

C) 19 m/s

Explanation:

The motion of the cannonball is a projectile motion, which consists of 2 independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- A uniformly accelerated motion (constant acceleration) along the vertical direction

As a result, we have the following:

- The horizontal velocity of the cannonball remains constant during the motion, and it is given by

v_x = u cos \theta

where

u = 25 m/s is the initial velocity

\theta=40^{\circ} is the angle

Substituting,

v_x = (25)(cos 40^{\circ})=19 m/s

- The vertical velocity keeps changing during the motion due to the acceleration of gravity. However, at the top of the trajectory, the vertical velocity is zero:

v_y = 0

This means that at the top of its path, the cannonball has only horizontal velocity, so its velocity is

C) 19 m/s

3 0
3 years ago
Why doesn't the moon move away from the earth
Aleks04 [339]
The earths gravitational pull keeps the moon orbiting around and from straying away from it and into the vast expanses of outer space.
4 0
4 years ago
Vector A⃗ has magnitude 8.00 m and is in the xy-plane at an angle of 127∘ counterclockwise from the +x–axis (37∘ past the +y-axi
WINSTONCH [101]

Answer:

293.7 degrees

Explanation:

A = - 8 sin (37) i + 8 cos (37) j

A + B = -12 j

B = a i+ b j , where and a and b are constants to be found

A + B = (a - 8 sin (37) ) i + ( 8cos(37) + b ) j

- 12 j = (a - 8 sin (37) ) i + ( 8cos(37) + b ) j

Comparing coefficients of i and j:

a = 8 sin (37) = 4.81452 m

b = -12 - 8cos(37) = -18.38908

Hence,

B = 4.81452 i  - 18.38908 j  ..... 4 th quadrant

Hence,

cos ( Q ) = 4.81452 / 12

Q = 66.346 degrees

360 - Q = 293.65 degrees from + x-axis in CCW direction

5 0
4 years ago
Why do quarterbacks throw the football with significant spin about its long axis?
Lera25 [3.4K]

(a) the principle of aerodynamic convergence

(b) the centripetal force

(c) Conservation of angular momentum

(d) Conservation of kinetic energy

(e) None of these

Conservation of angular momentum

Answer: Option C.

<u>Explanation:</u>

The law of conservation of angular momentum expresses that when no outer torque follows up on an article, no difference in precise force will happen.

The law of conservation of angular momentum expresses that the angular energy of a body that is the result of its snapshot of latency about the hub of revolution and its rakish speed about a similar pivot, can't change except if an outside torque follows up on the framework.

7 0
4 years ago
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