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PSYCHO15rus [73]
3 years ago
8

You are running late for class and are still in the hallway when the bell rings. The tardy bell is right outside your classroom

door, and your teacher is standing directly beneath it. If you are running towards the bell when it rings, which of the following best describes what you hear? (DOK 1)
Question 8 options:

A. You hear a higher pitch than your teacher


B. You hear a lower pitch than your teacher


C. You hear a louder pitch than your teacher


D. You hear the same pitch as your teacher
Physics
1 answer:
Sphinxa [80]3 years ago
5 0

Answer:

C

Explanation:

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The force required to compress a non-standard spring as a function of displacement from equilibrium x is given by the equation F
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Answer:

The equation which define the work done by spring is w = 45 x³ - 8 x²

Explanation:

Given as :

The force is the function of distance x

I.e F(x) = a x² - b x

where

a = 45 N/m²

b = 8 N/m

Now, Wok done = Force ×displacement

I.e W = F . ds

So , W = (a x² - b x) × x

or, W = (45 x² - 8 x) × x

Or, w = 45 x³ - 8 x²

So, the equation which define the work done by spring is w = 45 x³ - 8 x²

Hence The equation which define the work done by spring is w = 45 x³ - 8 x²  Answer

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Item 19 A student with arms outstretched stands on a platform that is rotating with a constant angular speed. The student then p
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An increase in angular speed due to conservation of energy priciple.

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A planet is orbiting a nearby star. Suppose that the star’s gravity increases over time. What effect will this increase most lik
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gas is compressed by a piston in a cylinder from an initial pressure of 1.0 bar and initial volume of 0.4m3 , to a final pressur
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The work was done on the gas. and internal energy of the gas will be -13459 J and -21649 J.

<h3>What is work done by gas?</h3>

When energy is moved from one store to another, work is completed. Work done on the gas is taken as -ve.

Given data;

Initial pressure(P₁)=1.0 bar

The initial volume, V₁=0.4m³

Final pressure(P₂) =1.4 bar.  

work is done on the gas., W=?(-ve)

Heat release= - 8.1 kJ

Change in the internal energy of the gas., ΔE

During the compression process, PV=C

P₁V₁=P₂V₂

1.0 bar × 0.4m³= 1.4 bar ×V₂

V₂=0.285 m³

\rm W=P_1V_1ln\frac{V_2}{V_1} \\\\\ \rm W=1.0 \times 0.4 ln\frac{0.285}{0.4} \\\\\ W=-13549 \ J

The work done on the gas will be -13459 J.

The internal energy is found as;

ΔE=q+w

ΔE= -8.1 ×10³ -13549

ΔE=-21649 J

Hence, work was done on the gas. and internal energy of the gas will be -13459 J and -21649 J.

To learn more about the work done by gas refer to;

brainly.com/question/12539457

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