Answer: The variable that you manipulate is called the independent variable. The variable that you measure is called the dependent variable.
Answer:
16.4287
Explanation:
The force and displacement are related by Hooke's law:
F = kΔx
The period of oscillation of a spring/mass system is:
T = 2π√(m/k)
First, find the value of k:
F = kΔx
78 N = k (98 m)
k = 0.796 N/m
Next, find the mass of the unknown weight.
F = kΔx
m (9.8 m/s²) = (0.796 N/m) (67 m)
m = 5.44 kg
Finally, find the period.
T = 2π√(m/k)
T = 2π√(5.44 kg / 0.796 N/m)
T = 16.4287 s
The voltage in the extension cord is 30 V.
The problem above can be solved using ohm's law
⇒ Formula:
V = IR.................. Equation 1
⇒ Where:
- V = Voltage in the extension cord
- I = Current flowing through the extension cord
- R = Resistance of the extension cord.
From the question, I think there was a slight error in the value of the current given it suppose to be 500 A, and not 5.00 A
⇒ Given:
⇒ Substitute these values into equation 1
Hence the voltage in the extension cord is 30 V
Learn more about voltage here: brainly.com/question/4429782
The best and most correct answer to the question is :
Alpha particles
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Hope this helped you :)
Answer:
Period of oscillation = 1.33 seconds
Explanation:
The period of oscillation is given by:
T = 2π√[I/(MgL)]
for I = 2MR² and L = R,
Given: L = 0.22m = R
T = 2π√[2R/g]
T = 2 × 3.142 Sqrt[( 2 × 0.22)/ 9.8]
T = 6.284 Sqrt(0.44/9.8)
T = 6.284 Sqrt(0.0449)
T = 6.284 × 0.2119
T = 1.33 sec
