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taurus [48]
3 years ago
7

Amy drove her car 253 Miles. The car used 10.07 gallons of gasoline on the drive. Estimate the cars gasoline mileage in miles pe

r gallon.
Mathematics
2 answers:
Elanso [62]3 years ago
8 0
I dont care about this 
yarga [219]3 years ago
4 0
The answer is 21.12 miles 
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PLEASE HELP FOR 100 POINTS AND BRAINLIEST! Find the unknown measures. Round lengths to the nearest hundredth and angle measures
Varvara68 [4.7K]

Answer:

A. BC ≈ 2.52; AB ≈ 1.28; m∠C = 27°

B. BC ≈ 1.28; AB ≈ 2.52; m∠C = 27°

C. BC ≈ 2.52; AB ≈ 1.28; m∠C = 117°

D. BC ≈ 1.28; AB ≈ 2.52; m∠C = 117°

3 0
2 years ago
4/15ths of 49. I know the answer but I can’t seem to figure out how to do the work so if someone could tell me the steps on how
DedPeter [7]

Answer:

.65

Step-by-step explanation:

Have you ever given up working on a math problem because you couldn’t figure out the next step? Wolfram|Alpha can guide you step by step through the process of solving many mathematical problems, from solving a simple quadratic equation to taking the integral of a complex function.

When trying to find the roots of 3x2+x–7=4x, Wolfram|Alpha can break down the steps for you if you click the “Show steps” button in the Result pod.

6 0
3 years ago
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
I'll give brainlest to first correct answer!!!
zvonat [6]

Answer:

I think there both negative but I'm not sure

Step-by-step explanation:

if one is a positive and one is a negative then reflect over the y axis they should both turn negative

6 0
2 years ago
You spinner that has 12 equal sides sections number 1 through 12 find each probability probability three or four
grigory [225]

Answer:

1 in 12 chance of landing on 3

1 in 12 chance of landing on 4

1 in 6 chance of landing on either 3 or 4

Step-by-step explanation:

12 equal sections means probability is 1 in 12 of landing on any one numbered section.

2 in 12 or 1 in 6 chance of landing on either of two numbered sections in one attempt.

4 0
2 years ago
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