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tino4ka555 [31]
3 years ago
11

Evaluate the expression for a = 3, b =12, and c = 4. 8ab/2bc PLZ I NEED HELP!!!

Mathematics
1 answer:
Law Incorporation [45]3 years ago
3 0
8(3)(12) is 288. 2(12)(4) is 96. 288/96 is 3. Answer is 3
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What would the domain and range of this graph be? In interval form, if it can be.
skad [1K]

Answer:

Step-by-step explanation:

Domain is the x values.  The interval of x-values that the function encompasses are from 0 inclusive to 7 exclusive.  In interval notation that is [0, 7).  The range is the y values.  The interval of y-values that the function encompasses are from what looks like -2 to 4.  In interval notation that is [-2, 4].  The domain goes from the lowest x-value to the highest; the range goes from the lowest y-value to the highest.

6 0
3 years ago
Jkl is an equilateral triangle jk= 13x+5,KL= 17X-19 AND JL= 8X+35​
stira [4]

Answer:

x = 6

Step-by-step explanation:

Since the triangle is equilateral then sides are congruent.

Equate any 2 sides and solve for x

13x + 5 = 8x + 35 ( subtract 8x from both sides )

5x + 5 = 35 ( subtract 5 from both sides )

5x = 30 ( divide both sides by 5 )

x = 6

JK = (13 × 6) + 5 = 78 + 5 = 83

KL = (17 × 6) - 19 = 102 - 19 = 83

JL = (8 × 6) + 35 = 48 + 35 = 83

ΔJKL is equilateral with side = 83

4 0
3 years ago
Find three consecutive odd integers such that the sum of the smallest and four times the largest is 61. Please list the numbers
Kipish [7]

Answer:

9,11,13

Step-by-step explanation:

Given: sum of the smallest integer and four times the largest integer out of three consecutive odd integers is 61

To list: numbers from least to greatest

Solution:

Let the three consecutive odd integers be x,x+2,x+4.

According to question,

x+4(x+4)=61\\x+4x+16=61\\5x=61-16\\5x=45\\x=9

So, the integers are x=9,x+2=9+2=11,x+4=9+4=13

Numbers from least to the greatest: 9,11,13

7 0
3 years ago
Calculate the area of the equilateral triangle using the formula for area of a regular polygon, and compare it to Bianca’s answe
8090 [49]

The calculated areas of both are the same instead of using the different formulas that are 43. 5 squared unit.

<h3>What is the area of a regular polygon?</h3>

The area of the polygon is the product of half of the apothem of the triangle and perimeter.

The area of the polygon = \frac{1}{2} \times h \times p

The side of the triangle is 10 units.

Apothem of an equilateral triangle

s = \frac{\sqrt{3} a}{6}

s= \sqrt{3} \times 10/6

s = 2.88

Here, a is the side of the triangle.

Thus the apothem of the triangle is 2.9 units.

The perimeter of the equilateral triangle is equal to the three times the sides.

Perimeter of the equilateral triangle ,

P = 3(10)

P = 30

Therefore, the perimeter of the equilateral triangle is 30 units.

The area of the equilateral triangle-

The area of the polygon = \frac{1}{2} \times h \times p

A = 1/2 \times 2.9 \times 30

A = 43.5

Thus the area of the equilateral triangle is 43.5 squared units.

Therefore, The calculated areas of both are the same instead of using the different formulas.

Learn more about the apothem;

brainly.com/question/10580427

7 0
2 years ago
Read 2 more answers
13 = m/4 + 7 can you show work too
lukranit [14]

The correct value of this equation is <u>m = </u><u>24</u>

<h3>Resolution method</h3>

This equation contains a fractional term. We note that the denominator of this equation is the <u>term 4</u>. Therefore, we will multiply the sides by <u>4</u>:

13 = m/4 + 7

13 . 4 = 4(m/4) + 7 . 4

52 = m + 28

Now, let's isolate the variable "as negative" and after the equality - we'll be subtracting the terms:

52 = m + 28

-m = 28 - 58

-m = -24

<u>m = 24</u>

Therefore, the correct value of this equation will be <u>m = 24</u>

7 0
2 years ago
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