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2 years ago

How do you solve |x-4| is less than or equal to 2?

Mathematics

1 answer:

Harlamova29_29 [7]2 years ago

7 0

Answer:

with your brain

Step-by-step explanation:

duhh8/7

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Solve the equation. Check your solution.

Varvara68 [4.7K]

Answer:

17/7

Step-by-step explanation:

2g+2(-8+2g)=1-g

2g-16+4g=1-g

6g-16=1-g

6g-(-g)-16=1

6g+g=1+16

7g=17

g=17/7

8 0

1 year ago

Omar needs at least $8 to buy lunch. Which number line represents this scenario?

Shtirlitz [24]

Answer:

I'd say none, as we're missing something in this problem. Make sure you've included everything to solve this problem. Thanks.

7 0

2 years ago

Graph F(x)=32x+2. Please

olga2289 [7]

Answer:

The required graph is shown below:

Step-by-step explanation:

Consider the provided graph $f(x)=32x+2$

The above function is a linear function.

We can draw the graph of the linear function with the help of two points.

Substitute x = 0 in $f(x)=32x+2$

$f(0)=32(0)+2$

$f(0)=2$

Hence, the coordinates are (0,2)

Substitute f(x) = 0 in $f(x)=32x+2$

$0=32x+2$

$32x=-2$

$x=-0.0625$

Hence, the coordinates are (-0.0625,0)

Now join the above points.

The required graph is shown below:

5 0

2 years ago

Read 2 more answers

The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of

kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

$A=\frac{\sqrt{3} }{4} a^{2}$

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

$A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}$

$A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}$

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

$A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}$

$A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}$

Now, comparing areas:

$\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )$

$\frac{A_{1}}{A_{2}} =$ 2.25

The area of ΔABC is 2.25x greater than the area of ΔDEF.

7 0

2 years ago

Ignore my handwriting but here’s some math i need for tomorrow

Vitek1552 [10]

FYI - 14,15,16 are correct.

17. a) 7 (nearest integer), b) 6.8 (nearest tenth)

18. a) 14 (nearest integer), b) 13.8 (nearest tenth)

19. $\sqrt{40}$ --> simplified to = 2 $\sqrt{10}$

-- let me know if you have any questions regarding this.

6 0

2 years ago