2 years ago

Easy Algebra 2 Rational Expressions question

Mathematics

1 answer:

Ostrovityanka [42]2 years ago

4 0

Set the bottom equal to 0

x - 8 = 0
x = 8

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At the moment a hot cake is put in a cooler, the difference between the cake's and the cooler's temperature is 50° Celsius. This

dybincka [34]

Answer:

$D(t)=50(0.8)^t$

Step-by-step explanation:

We are given that

Initially the difference between the cake's and the cooler's temperature ,a=50 degree Celsius

$r=\frac{1}{5}/min$

We have to find the function that gives the temperature difference in degrees Celsius D(t).

We know that

$D(t)=a(1-r)^t$

Substitute the values

$D(t)=50(1-\frac{1}{5})^t=50(1-0.2)^t$

$D(t)=50(0.8)^t$

This is required function that gives the temperature difference in degrees Celsius.

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