How much energy does an electric hair dryer use if it draws 8.3 amps of current when using 120 volts for 5.0 minutes?
2 answers:
<u>Answer:</u> The energy drawn by electric hair dryer is 2,98,800 J
<u>Explanation:</u>
To calculate the power of the electric hair dryer, we use the equation:
where,
P = power of electric hair dryer
I = Current of electric hair dryer = 8.3 A
V = voltage of electric hair dryer = 120 V
Putting values in above equation, we get:
To calculate the energy of electric hair dryer, we use the equation:
where,
E = energy of electric hair dryer = ?
P = Power of electric hair dryer = 996 W
t = time taken = 5.0 min = 300 s (Conversion factor: 1 min = 60 sec)
Putting values in above equation, we get:
Hence, the energy drawn by electric hair dryer is 2,98,800 J
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Answer:
Kp = 1.41 x 10⁻⁶
Explanation:
We have the chemical equation:
2 A(g) + 3 B(g)⇌ C(g)
In which A and B are the reactants and C is the product. We calculate first the change in the number of moles of gas (Δn or dn):
dn= (sum moles products - sum moles reactants)
= (moles C - (moles A + moles B))
= (1 - (2+3))
= 1 - 5
= -4
We have also the following data:
Kc = 63.2
T= 81∘C + 273 = 354 K
R = 0.082 L.atm/K.mol (it is a constant)
Thus, we introduce the data in the mathematical expression for the relation between Kp and Kc:
= (0.082 L.atm/K.mol x 354 K)⁻⁴ = 1.41 x 10⁻⁶