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Olin [163]
3 years ago
11

What is the percent Hydrogen in glucose

Chemistry
1 answer:
Ivan3 years ago
7 0
Glucose- C6H12O6
12+6+6=24
H=12
12/24=0.5
0.5x100
=50%
You might be interested in
27. The density of nickel is 8.91 g/cm3. How large a cube, in cm3, would contain 2.00 x 10^24 atoms of nickel? Use dimensional a
jok3333 [9.3K]

Answer : The volume of the cube is, 21.88cm^3

Solution : Given,

Density of nickel = 8.91g/cm^3

Number of nickel atoms = 2\times 10^{24}

Molar mass of nickel = 58.7 g/mole

First we have to calculate the moles of nickel.

As, 6.022\times 10^{23} atoms form 1 mole of nickel

So, 2\times 10^{24} atoms form \frac{2\times 10^{24}}{6.022\times 10^{23}}=3.321 moles of nickel

The moles of nickel = 3.321 moles

Now we have to calculate the mass of nickel.

\text{ Mass of Ni}=\text{ Moles of Ni}\times \text{ Molar mass of Ni}

\text{ Mass of Ni}=(3.321moles)\times (58.7g/mole)=194.94g

The mass of nickel = 194.94 g

Now we have to calculate the volume of nickel.

Density=\frac{Mass}{Volume}

8.91g/cm^3=\frac{194.94g}{Volume}

Volume=21.88cm^3

Therefore, the volume of the cube is, 21.88cm^3

4 0
3 years ago
How many moles of carbon are there in a 0.70 g (3.5 carat) diamond?
maksim [4K]

Answer:

3.5 x 10^22 moles of carbon are there in a 0.70 g (3.5 carat) diamond.

Explanation:

In case of diamond, the number of atoms is the same as the number of molecules.

7 0
3 years ago
What type of energy transformation is taking place when natural gas is used to heat water
kifflom [539]
That is thermal energy 
8 0
3 years ago
How many atoms are present in 34.69 moles of Mg
shusha [124]
<span>Avogadro's number. 

1 mole of any substance, molecule or element is equal to a certain amount of atom. 

6.022 x 10^23 is the Avogradro's constant. 

Magnesium Oxide is a compound. therefore if you have 30.3 g of it (1 mol), it will have the same number of atoms. 

34.69 moles of MgO has 208.9 x 10^23 number of atoms. 

2.089 x 10^25 is also a correct answer.</span><span>
</span>
7 0
3 years ago
Find the density of a cube on Earth that weighs 1.5 kg and has a side-length of 10 cm.
Inga [223]

Answer:

1.5g/cm³

Explanation:

density=mass÷volume

mass= 1.5kg (<em>c</em><em>h</em><em>a</em><em>n</em><em>g</em><em>e</em><em> </em><em>i</em><em>n</em><em>t</em><em>o</em><em> </em><em>g</em>) = 1500g

volume of the cube = 10×10×10 = 1000cm³

density= divide 1500g÷1000cm = 1.5g/cm³

<h2>Density= 1.5g/cm³</h2>

YOUR WELCOME!

4 0
3 years ago
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