Ethane has the formula C2H6.
From the periodic table:
molecular mass of carbon = 12 grams
molecular mass of hydrogen = 1 gram
Therefore:
molar mass of ethane = 2(12) + 6(1) = 30 grams
This means that each 30 grams of ethane contains 6 grams of hydrogen. To know how many grams of hydrogen are in 3000 grams of ethane (3 kg), we will simply use cross multiplication as follows:
mass of hydrogen = (3000 x 6) / 30 = 600 grams
Answer:
the real tricky one question
Explanation:
Answer:
n=6 to n=3 (B)
Explanation:
Energy of an electron present in the
orbit is directly proportional to
.Hence a transistion from one orbit to another orbit emits an energy proportional to the difference of their squares of the orbits. that is if an electron travels from orbit n1 to orbit n2 then it emits an energy corresponding to
.So in the above question the highest energy emission occurs when an electron moves from n=6 to n=3.(Highest difference of energy levels).
Ok to answer this question we firsst need to fin the number of mol of Urea (CH4N2O). to do this we simply :
1 mol of urea =15/60.055 = 0.25mol
therefore 200g of water contain 0.25mol
the next step is to determine the malality of our solution in 200g of water, to do this we say:
200 g = 1Kg/1000g = 0.2kg
therefor 0.25mol/0.2Kg = 1.25mol/kg
and from the equation:
we know that i = 1
we are given Kf
b is the molality that we just calculated
therefore;
the solutions freezing point is -2.325°C
1 Oz is 28.3495 grams
hope this helps!