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3 years ago

What is Force and its effects ?

Physics

2 answers:

Artist 52 [7]3 years ago

7 0

Force is a Push or Pull acting on a body

Elanso [62]3 years ago

5 0

Hi pupil here's your answer :::

➡➡➡➡➡➡➡➡➡➡➡➡➡

Force = It is a push or pull which either changes or tends to change the state of rest or of uniform motion of a body.

In our everyday life, we use force, quite frequently to perform various activities, some examples are Kicking a football, squeezing a tube of toothpaste lifting a book, catching a ball opening a door etc.

$\boxed{Effects\:of\:Force:}$

1 ) Move a body lying at rest :

@ Kicking a Stationary Football.
@ Lifting a book kept on a table top.
@ Hitting a stationary ball with a bat.

2) Stop a moving body :

@ A moving ball can be stopped by the force of our hand.
@ A moving ball can stop on its own due to the force of friction.
@ A rotating top can be stopped by a force exerted by our hands.

3) Change the speed of a moving body :

@ If a person pushes a moving swing, it will move faster.
@ When more forces applied on the pedals buy a cyclist, speed of cycle increases

4) Change the direction of a moving body :

@ When a batsman hit the ball with his bat, the direction of the moving ball changes.
@A Carrom counter changes its direction after a collision.
@ A football player hitting a ball coming towards him, towards the goal post.

5) Change the shape of an object :

@ When we squeeze toothpaste tube, it gets flattened.
@ When we stretch a rubber band, its shape and size changes.
@ On stretching a spring, its length changes

⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅

Hope this helps ..........

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The two structural members, one of which is in tension and the other in compression, exert the indicated forces on joint o. dete

melisa1 [442]

We're going to remedy it with the parallelogram law.
$\alpha$ = one hundred eighty - 30 - 70 = eighty degrees
R = sqrt(2^2 + 3^2 - 2(2)(three) cos(80)
R = three.30 kN, we can conclude now that the value of the ensuing of R is 3.30 kN

sin $\beta$ /3 = sin(eighty)/three.304 = 63.4 stages

3.3 kN
180 + 33.4 = 213.4 degrees
63.4 - 30 = 33.4

4 0

4 years ago

Three identical balls are thrown from the same height off a tall building. They are all thrown with the same speed, but in diffe

koban [17]

Answer:

three balls have the same speed

Explanation:

In a parabolic motion we have that

$v_{x}=v_{0}cos\alpha\\v_{y}=-gt+v_{0}sin\alpha\\v=\sqrt{v_{x}^{2}+v_{y}^{2}}\\$

but the time just before the balls hit the ground is

$t=\frac{2v_{0}sin\alpha}{g}$

Hence we have

ball A

$v=\sqrt{v_{0}^{2}cos^{2}(0)+(-g\frac{2v_{0}sin(0)}{g}+v_{0}sin(0))^{2}}\\v=\sqrt{v_{0}^{2}}=v_{0}$

ball B

$v=\sqrt{v_{0}^{2}cos^{2}(45)+(-g\frac{2v_{0}sin(45)}{g}+v_{0}sin(45))^{2}}\\v=\sqrt{v_{0}^{2}(\frac{\sqrt{2}}{2})^{2}+v_{0}^{2}(\frac{\sqrt{2}}{2})^{2}}\\v=\sqrt{v_{0}^{2}}=v_{0}$

ball C

$v=\sqrt{v_{0}^{2}cos^{2}(-45)+(-g\frac{2v_{0}sin(-45)}{g}+v_{0}sin(-45))^{2}}\\v=\sqrt{v_{0}^{2}(\frac{\sqrt{2}}{2})^{2}+v_{0}^{2}(\frac{\sqrt{2}}{2})^{2}}\\v=\sqrt{v_{0}^{2}}=v_{0}$

Hence, all three balls have the same speed just before hit the groug

vA=vB=vC

I hope this is useful for you

regards

5 0

3 years ago

Janet jumps off a high diving platform with a horizontal velocity of 2.8 meters per second in lands in the_________.

Inessa05 [86]

Answer:

Janet jumps off a high diving platform with a horizontal velocity of 2.89 m per s and lands in the water 1.5 s later. How high is the platform?

Platform is 11.025 meters high .

Explanation:

we have Vx = 2.89 m/s

time taken = 1.5 seconds

height of the platform = ?

so,

As Janet is jumping from a high diving platform from a certain unknown height their must be involvement of gravity in action.

we can use,

h = Vi*t+(1/2)*g*t^2

where ,

h = height

Vi = initial horizontal velocity that will be zero

t = time in seconds

g = gravity due to acceleration

now put the values

h = 0+(1/2)*(9.8)*(1.5)^2

h = 11.025-m

6 0

3 years ago

A bomb at rest at the origin of an xy-coordinate system explodes into three pieces. Just after the explosion, one piece, of mass

ValentinkaMS [17]

Answer:

Explanation:

a ) It is given that bomb was at rest initially , so , its momentum before the explosion was zero.

b ) We shall apply law of conservation of momentum along x and y direction separately because no external force acts on the bomb.

If v be the velocity of the third part along a direction making angle θ

with x axis ,

x component of v = vcosθ

So momentum along x axis after explosion of third part = mv cosθ

= 10 v cosθ

Momentum along x of first part = - 5 x 42 m/s

momentum of second part along x direction =0

total momentum along x direction before explosion = total momentum along x direction after explosion

0 = - 5 x 42 + 10 v cosθ

v cosθ = 21

Similarly

total momentum along y direction before explosion = total momentum along y direction after explosion

0 = - 5 x 38 + 10 v sinθ

v sinθ= 21

squaring and and then adding the above equation

v² cos²θ +v² sin²θ = 21² +19²

v² = 441 + 361

v = 28.31 m/s

Tanθ = 21 / 19

θ = 48°

6 0

3 years ago

Does anyone understand This question if you do can you tell me the answer

leonid [27]

Answer:

50N increasing

Explanation:

it looks like we want the net force. this is the sum of all forces acting on the object. here the problem is extremely simplified and we are even given the values of force. this looks like the rocket is producing an upward force of 160 newtons. it also looks like maybe weight (gravity) and drag (air resistance) are producing downward force against the rocket. we can say those would be subtracting from the amount of upwards force. so 160-40-70=50N. since the force is positive that means we will still have a magnitude of force vector that points upward and so we will increase.

6 0

3 years ago