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eduard
3 years ago
12

What force involves the attraction between objects with mass?

Physics
1 answer:
Damm [24]3 years ago
4 0
Gravitational force or gravitational pull involves the attraction between objects with mass
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65. A length of wire is bent into a closed loop and a magnet is plunged into it, inducing a voltage and, consequently, a current
natulia [17]

Answer:

Resistance of the second wire is twice the first wire.

Explanation:

Let us first see the formula of resistance;

R = pxL/A

Here L is the lenght of the wire, A the area and p is the resistivity of wire.

As we are given that the length of second wire is double than that of the first wire, hence the resistance of second wire would be double.

Since we have two loop in second case, inducing double voltage but as resistance is doubled so the current would remain same according to ohms law

I = V/R

6 0
3 years ago
Read 2 more answers
You're driving your new sports car at 85 mph over the top of a hill that has a radius of curvature of 525 m.
Bumek [7]

Explanation:

It is given that,

Speed of the sports car, v = 85 mph = 37.99 m/s

The radius of curvature, r = 525 m

Let W_N is the normal weight and W_A is the apparent weight of the person. Its apparent weight is given by :

W_A=mg-\dfrac{mv^2}{r}

So, \dfrac{W_A}{W_N}=\dfrac{mg-\dfrac{mv^2}{r}}{mg}

\dfrac{W_A}{W_N}=\dfrac{g-\dfrac{v^2}{r}}{g}

\dfrac{W_A}{W_N}=\dfrac{9.8-\dfrac{(37.99)^2}{525}}{9.8}

\dfrac{W_A}{W_N}=0.719

or

\dfrac{W_A}{W_N}=71.9\%

Hence, this is the required solution.

5 0
4 years ago
Volume of a cylinder with a diameter of 1.55 cm and a height of 1.34 cm
Bogdan [553]

Answer:

2.53 cm³

Explanation:

Volume of cylinder = πr²h; where h is the height and r is the radius and

π = 3.14 approx.

Volume = 3.14 * (1.55/2)² * 1.34 = 2.53 cm³

I divided 1.55 by 2 because we were given the diameter and not radius. Diameter = radius / 2

4 0
3 years ago
A free falling object has the velocity time graph shown. What is the objects displacement between 0.0 and 6.0s
zloy xaker [14]

For free fall motion the displacement can be found by graphically as well as by kinematics equation

Here acceleration of object is constant as it fall due to gravity so we can use

d = v_i * t + \frac{1}{2}at^2

here if body starts with zero initial speed then we can say

d = 0 + \frac{1}{2}*9.8*t^2

here we need to find the displacement from t = 0 to t = 6s

so we can say

d = \frac{1}{2}*9.8*6^2

d = 176.4 m

so the displacement will be 176.4 m

in order to find the displacement from the graph of velocity and time we need to find the area under the graph for given time interval that will also give us same displacement for given period of time.

6 0
4 years ago
Read 2 more answers
. Find the buoyant force exerted on a ball with radius of 2 meters, when the ball is entirely immersed in the water.
almond37 [142]

Explanation:

Buoyancy force is equal to the weight of the displaced fluid:

B = ρVg

where ρ is the density of the fluid,

V is the volume of the displaced fluid,

and g is the acceleration due to gravity.

The fluid is water, so ρ = 1000 kg/m³.

The volume displaced is that of a sphere with radius 2 m:

V = 4/3 π r³

V = 4/3 π (2 m)³

V ≈ 33.5 m³

The buoyancy force is therefore:

B = (1000 kg/m³) (33.5 m³) (9.8 m/s²)

B ≈ 328,400 N

Round as needed.

8 0
3 years ago
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