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Svetradugi [14.3K]
3 years ago
15

Janet jumps off a high diving platform with a horizontal velocity of 2.8 meters per second in lands in the_________.

Physics
1 answer:
Inessa05 [86]3 years ago
6 0

Answer:

Janet jumps off a high diving platform with a horizontal velocity of 2.89 m per s and lands in the water 1.5 s later. How high is the platform?

Platform is 11.025 meters high .

Explanation:

we have Vx = 2.89 m/s

time taken = 1.5 seconds

height of the platform = ?

so,

As Janet is jumping from a high diving platform from a certain unknown height their must be involvement of gravity in action.

we can use,

h = Vi*t+(1/2)*g*t^2

where ,

h = height

Vi = initial horizontal velocity that will be zero

t = time in seconds

g = gravity due to acceleration

now put the values

h = 0+(1/2)*(9.8)*(1.5)^2

h = 11.025-m

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Read 2 more answers
An electron with a speed of 0.95c is emitted by a supernova, where cc is the speed of light. What is the magnitude of the moment
krok68 [10]

Answer:

2.59×10¯²² Kgm/s

Explanation:

Data obtained from the question include:

Velocity of electron = 0.95c

Momentum =?

Next, we shall determine the velocity of the electron. This can be obtained as follow:

Velocity of electron = 0.95c

Velocity of Light (c) = 3×10⁸ m/s

Velocity of electron = 0.95c

Velocity of electron = 0.95 × 3×10⁸

Velocity of electron = 2.85×10⁸ m/s

Finally, we shall determine the mometum of the electron.

Momentum is simply defined as the product of mass and velocity. Mathematically, it is expressed as:

Momentum = mass x Velocity

Thus, with the above formula, we calculate the momentum of the electron as follow:

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Velocity of electron = 2.85×10⁸ m/s

Momentum of electron =?

Momentum = mass x Velocity

Momentum = 9.1×10¯³¹ × 2.85×10⁸

Momentum = 2.59×10¯²² Kgm/s

Therefore, the momentum of the electron is 2.59×10¯²² Kgm/s

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3 years ago
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