All categories

3 years ago

Janet jumps off a high diving platform with a horizontal velocity of 2.8 meters per second in lands in the_________.

Physics

1 answer:

Inessa05 [86]3 years ago

6 0

Answer:

Janet jumps off a high diving platform with a horizontal velocity of 2.89 m per s and lands in the water 1.5 s later. How high is the platform?

Platform is 11.025 meters high .

Explanation:

we have Vx = 2.89 m/s

time taken = 1.5 seconds

height of the platform = ?

so,

As Janet is jumping from a high diving platform from a certain unknown height their must be involvement of gravity in action.

we can use,

h = Vi*t+(1/2)*g*t^2

where ,

h = height

Vi = initial horizontal velocity that will be zero

t = time in seconds

g = gravity due to acceleration

now put the values

h = 0+(1/2)*(9.8)*(1.5)^2

h = 11.025-m

You might be interested in

How many grams of co2 are in 3 moles of the compound

Ber [7]

Answer:132.0285

Explanation: Hope this helps!

7 0

3 years ago

Read 2 more answers

Explain why a steel block sinks but a steel ship floats

uysha [10]

Answer:

Fluids exert forces on objects because of many molecules of the fluid that continuously collide with the surfaces of the object immersed in the fluid. ... A steel boat floats on water but a steel block does not because the block has more weight than the steel boat due to the buoyant force.

Explanation:

3 0

3 years ago

What voltage battery would you need to send 2.5A of current through a light bulb of resistance 3.6 ohm

nadezda [96]

<h3><u>Given</u> :</h3>

Current flow light bulb = 2.5 $\sf{A}$

Resistance of light bulb = 3.6Ω

We have to find voltage of battery $.$

<h3><u>Solution</u> :</h3>

➠ As per ohm's law, current flow through a conductor is directly proportional to the applied potential difference.

➝ V ∝ I

➝ <u>V = I × R</u>

Where, R is the resistance of conductor.

⇒ V = I × R

⇒ V = 2.5 × 3.6

⇒ <u>V = 9 volt</u>

8 0

3 years ago

An interference pattern is produced by light with a wavelength 580 nm from a distant source incident on two identical parallel s

irakobra [83]

Answer:

Explanation:

1 )

Here

wave length used that is λ = 580 nm

=580 x 10⁻⁹

distance between slit d = .46 mm

= .46 x 10⁻³

Angular position of first order interference maxima

= λ / d radian

= 580 x 10⁻⁹ / .46 x 10⁻³

= 0.126 x 10⁻² radian

2 )

Angular position of second order interference maxima

2 x 0.126 x 10⁻² radian

= 0.252 x 10⁻² radian

3 )

For intensity distribution the formula is

I = I₀ cos²δ/2 ( δ is phase difference of two lights.

For angular position of θ1

δ = .126 x 10⁻² radian

I = I₀ cos².126x 10⁻²/2

= I₀ X .998

For angular position of θ2

I = I₀ cos².126x2x 10⁻²/2

= I₀ cos².126x 10⁻²

8 0

3 years ago

For a caffeinated drink with a caffeine mass percent of 0.65% and a density of 1.00 g/mL, how many mL of the drink would be requ

slava [35]

Explanation:

First we will convert the given mass from lb to kg as follows.

157 lb = $157 lb \times \frac{1 kg}{2.2046 lb}$

= 71.215 kg

Now, mass of caffeine required for a person of that mass at the LD50 is as follows.

$180 \frac{mg}{kg} \times 71.215 kg$

= 12818.7 mg

Convert the % of (w/w) into % (w/v) as follows.

0.65% (w/w) = $\frac{0.65 g}{100 g}$

= $\frac{0.65 g}{(\frac{100 g}{1.0 g/ml})}$

= $\frac{0.65 g}{100 ml}$

Therefore, calculate the volume which contains the amount of caffeine as follows.

12818.7 mg = 12.8187 g = $\frac{12.8187 g}{\frac{0.65 g}{100 ml}}$

= 1972 ml

Thus, we can conclude that 1972 ml of the drink would be required to reach an LD50 of 180 mg/kg body mass if the person weighed 157 lb.

5 0

3 years ago