Answer:
Vertical Asymptote:
Horizontal asymptote:
it does not exist
Step-by-step explanation:
we are given
Vertical asymptote:
we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf
we know that any log becomes -inf when value inside log is zero
so, we can set value inside log to zero
and then we can solve for x
we get
Horizontal asymptote:
we know that
horizontal asymptote is a value of y when x is +inf or -inf
For finding horizontal asymptote , we find lim x-->inf or -inf
so, it does not exist
Answer:
height = 12 cm
base length = 4 cm
Step-by-step explanation:
area of a triangle
base length × height / 2
x = height
y = base length
x = y + 8
24 = y × (y + 8) / 2
48 = y × (y + 8) = y² + 8y
squared equation
y² + 8y - 48 = 0
solution
y = (-b ± sqrt(b² - 4ac))/(2a)
a = 1
b = 8
c = -48
y = (-8 ± sqrt(64 - 4×-48))/2 = (-8 ± sqrt(64 + 192))/2 =
= (-8 ± sqrt(256))/2 = (-8 ± 16)/2 = -4 ± 8
y1 = -4 + 8 = 4 cm
y2 = -4 - 8 = -12
but a negative base length did not make any sense, so only y = 4 remains.
x = y + 8 = 4 + 8 = 12 cm
U have to times by 2 it will it will change
Answer:
The picture is not up. May you please upload it. Thank you:)
Step-by-step explanation:
Do you have the answers to the rest/multiple choice part of the test ??
