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Elina [12.6K]
4 years ago
7

PLEASE HELp PLEASE

Mathematics
2 answers:
bagirrra123 [75]4 years ago
6 0

Answer:

Part A. For x, we’ll use 1, 2, 3, 4, and 5. Now, we have to plug in the x-values to get f(x) (or y). I’ll do the first two w/ explanations then just give the answers. when x= 1, f(1)= 2/3•1-1. solve accordingly, you get -0.3. Next, when x= 2, f(2)= 2/3•2-1. Solve and you get f(2)= 0.3. when completing and solving for the other 3 x-values, use the same process and plug into the chart with corresponding numbers. A calculator may be helpful.

Part B. Just graph, use the x-values for x and the y-values for y. if u don’t know how to graph u may want to look back on some of your lessons if available.

Thanks.

Step-by-step explanation:

Ket [755]4 years ago
4 0
Is this it ?? or no........
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Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b
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The roots of the given polynomials exist  $x=8+\sqrt{10}$, and $x=8-\sqrt{10}$.

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

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Therefore by using the formula we have

$x^{2}-16 x+54=0$$

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Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\

$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\

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Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$, and

$x=8-\sqrt{10}$.

To learn more about quadratic equations refer to:

brainly.com/question/1214333

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