Answer:
The volume of the dry gas at STP is = 0.4314 L
Explanation:
We are given:
Total vapor pressure = 740 mmHg
Also, considering Vapor pressure of water = 23.78 mmHg
Vapor pressure of gas = Total vapor pressure - Vapor pressure of water = (740 - 23.78) mmHg = 716.22 mmHg
We use the equation given by ideal gas which follows:
where,
P = pressure of the gas = 716.22 mmHg
V = Volume of the gas = 500 mL = 0.5 L ( 1 ml = 0.001 L )
T = Temperature of the gas =
R = Gas constant =
n = number of moles of gas = ?
Putting values in above equation, we get:
At STP, 1 mole of gas yields a volume of 22.4 L
So,
0.01926 mole of gas yields volume of ![0.01926\times 22.4\ L](https://tex.z-dn.net/?f=0.01926%5Ctimes%2022.4%5C%20L)
<u>Hence, the volume of the dry gas at STP is = 0.4314 L</u>