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DanielleElmas [232]
3 years ago
7

A.1 B.2 C.3 D.4 Please help!

Chemistry
2 answers:
VashaNatasha [74]3 years ago
6 0
I think its 3 precipitation.
Lena [83]3 years ago
6 0
The answer is a i think


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A compound is composed of only C, H, and O. The combustion of a 0.519-g sample of the compound yields 1.24 g of CO 2 and 0.255 g
vredina [299]

Answer:

      \large\boxed{\large\boxed{C_3H_3O}}

Explanation:

<u>1. Calculate the mass of C in 1.24 g of CO₂</u>

   1.24gCO_2\times \dfrac{12.011gC}{44.01gCO_2}=0.3384gC

<u>2. Calculate the mass of H in 0.255g of H₂O</u>

     0.255gH_2O\times \dfrac{2.016gH}{18.015gH_2O}=0.02854gH

<u />

<u>3. Calculate the mass of O by difference</u>

     0.519g-0.3384g-0.02854g=0.15206g

<u>4. Convert every mass to number of moles:</u>

  • C: 0.3384g / (12.011g/mol) = 0.02817 mol
  • H: 0.02854g / (1.008g/mol) = 0.02831 mol
  • O: 0.15206g / (15.999g/mol) = 0.009504 mol

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<u>5. Divide every number of moles by the least number of moles (0.009504):</u>

  • C: 0.02817/0.009504 = 2.96 ≈ 3
  • H: 0.02831 / 0.009504 ≈ 3
  • O: 0.009504 / 0.009504 = 1

<u>6. Those numbers are the respective subscripts in the empirical formula:</u>

     C_3H_3O

7 0
3 years ago
Coolant is added to car radiators to keep the water from becoming a gas and evaporating when the car gets hot. Which physical pr
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Answer:

Boiling point.

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If 2.0 liters of oxygen gas react with excess carbon monoxide at 273 K and 1.00 atm, how many liters of carbon dioxide can be pr
vlada-n [284]
The given condition is STP, under this condition, gas has a rule of 22.4 L per mole. And the given equation is already balanced. The ratio of mole number is the same as the ratio of the volume and is also the same as the ratio of coefficients. So the answer is 4.0 liters. 
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What properties do molecules usually share?
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They contain atoms including nucleus proton electron and neutron
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3 years ago
The temperature of 75 mL of gas is decreased from 450 K to 150 K while the pressure is held constant. What is the new volume of
irinina [24]

Answer: Option A) 25mL

Explanation:

Given that,

Original volume of gas (V1) = 75mL

Original temperature of gas (T1) = 450K

New volume V2 = ?

New temperature T2 = 150K

Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

V1/T1 = V2/T2

75mL/450K = V2/150K

To get the value of T2, cross multiply

75mL x 150K = 450K x V2

11250mL•K = 450K•V2

Divide both sides by 450K

11250mL•K / 450K = 450K•V2/450K

25mL = V2

Thus, the new volume of the gas is 25mL

3 0
3 years ago
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