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DanielleElmas [232]
3 years ago
7

A.1 B.2 C.3 D.4 Please help!

Chemistry
2 answers:
VashaNatasha [74]3 years ago
6 0
I think its 3 precipitation.
Lena [83]3 years ago
6 0
The answer is a i think


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1. Calculate how many moles of glycine are in a 130.0-g sample of glycine.2. Calculate the percent nitrogen by mass in glycine.
Alexxx [7]

Answer:

n=1.732mol

\% N=18.7\%

Explanation:

Hello!

In this case, since the molecular formula of glycine is C₂H₅NO₂, we realize that the molar mass is 75.07 g/mol; thus, the moles in 130.0 g of glycine are:

n=130.0g*\frac{1mol}{75.07 g}\\\\ n=1.732mol

Furthermore, we can notice 75.07 grams of glycine contains 14.01 grams of nitrogen; thus, the percent nitrogen turns out:

\% N=\frac{14.01}{75.07}*100\% \\\\\% N=18.7\%

Best regards!

4 0
3 years ago
Which statement correctly compares sound and light waves?
Mrac [35]

Answer:

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Explanation:

5 0
3 years ago
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Vinil7 [7]

Answer:

....,................................

Explanation:

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8 0
2 years ago
What are the products of this reaction? (High temperature)<br> Na2SO4 * 10H2O + C —&gt; ????
Thepotemich [5.8K]

Answer:

A chemical equation can be described as a symbolic representation of a chemical reaction. It can be written in the form of words or symbols.

The following chemical reaction can be completed as :

Na2SO4·10H2O + 2C = Na2S + 10H2O + 2CO2

Sodium Sulfate Decahydrate + Diamond = Sodium Sulfide + Water + Carbon Dioxide

The products of the reaction are:

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6 0
3 years ago
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balu736 [363]

Answer:

MgO

Explanation:

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