The answer is B Digestion
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Answer:
1.5 atm is the pressure of dinitrogen tetroxide after equilibrium is reached the second time.
Explanation:
![2NO_2(g)\rightleftharpoons N_2O_4(g)](https://tex.z-dn.net/?f=2NO_2%28g%29%5Crightleftharpoons%20N_2O_4%28g%29)
initially
4.9 atm 0
At equilbrium:
(4.9-2p) p
Pressure of nitrogen dioxide gas at equilibrium = 2.7 atm
So, (4.9-2p) = 2.7 atm
p = 1.1 atm
The value of equilibrium constant
:
![K_p=\frac{p_{N_2O_4}}{(p_{NO_2})^2}](https://tex.z-dn.net/?f=K_p%3D%5Cfrac%7Bp_%7BN_2O_4%7D%7D%7B%28p_%7BNO_2%7D%29%5E2%7D)
![K_p=\frac{p}{(4.9-2p)^2}](https://tex.z-dn.net/?f=K_p%3D%5Cfrac%7Bp%7D%7B%284.9-2p%29%5E2%7D)
![K_p=\frac{1.1 atm}{(4.9-2\times 1.1)^2}=0.1509](https://tex.z-dn.net/?f=K_p%3D%5Cfrac%7B1.1%20atm%7D%7B%284.9-2%5Ctimes%201.1%29%5E2%7D%3D0.1509)
After addition of 1.2 atm of nitrogen dioxide gas more to the flask,will the reestablish an equilibrium in flask.
![2NO_2(g)\rightleftharpoons N_2O_4(g)](https://tex.z-dn.net/?f=2NO_2%28g%29%5Crightleftharpoons%20N_2O_4%28g%29)
(2.7+1.2) atm 1.1 atm
At second equilibrium
(2.7+1.2-2x) atm (1.1+x) atm
The expression of
:
![K_p=\frac{p_{N_2O_4}}{(p_{NO_2})^2}](https://tex.z-dn.net/?f=K_p%3D%5Cfrac%7Bp_%7BN_2O_4%7D%7D%7B%28p_%7BNO_2%7D%29%5E2%7D)
![0.1509=\frac{(1.1+x)}{(2.7+1.2-2x)^2}](https://tex.z-dn.net/?f=0.1509%3D%5Cfrac%7B%281.1%2Bx%29%7D%7B%282.7%2B1.2-2x%29%5E2%7D)
Solving for x:
x = 0.3827 atm
The pressure of dinitrogen tetroxide after equilibrium is reached the second time:
(1.1+x) atm = (1.1+0.3827) atm =1.4827 atm ≈ 1.5 atm
1.5 atm is the pressure of dinitrogen tetroxide after equilibrium is reached the second time.
On the inside of the refrigerator door are NOT required Permanent safety markings
<u>Explanation:</u>
Normally in red color the Permanent safety markings arre done. That are wanted on household refrigerators that accept any refrigerant with an A3 flammability grade such as HCs, on or near any evaporators, any exposed refrigerant tubing, near the machine compartment, and on the exterior of the refrigerator.
Each of these markings shall be in words no short than 6.4 mm (1/4 inch) long. Room residents should remove the place quickly regarding the unexpected release of this refrigerant. "DANGER—Risk of Fire or Explosion. Flammable Refrigerant Used. To Be Repaired Only By Trained Service Personnel. Do Not Puncture Refrigerant Tubing.” is the quote to be marked in the above specified places.
Answer:
-3.1 m/s²
Explanation:
Given data
- Initial speed (v₀): 20 m/s
- Final speed (vf): 0 m/s (the automobile stops)
- Elapsed time (t): 6.5 seconds
- Acceleration (a): to be determined
We can determine the acceleration of the automobile using the following kinematic expression.
a = Δv / t
a = vf - v₀ / t
a = (0 m/s - 20 m/s) / 6.5 s
a = -3.1 m/s²
A mixture of 3.05-atm N₂(g) and 5.29-atm He(g) exerts a total pressure of 8.34 atm.
<h3>What does Dalton's law of partial pressure state?</h3>
Dalton's law states that in a mixture of non-reacting gases, the total pressure exerted is equal to the sum of the partial pressures of the individual gases.
A mixture of N₂(g) and He(g) exerts a total pressure of 8.34 atm, while the partial pressure of N₂ is 3.05 atm.
We will use Dalton's law to calculate the partial pressure of He.
P = pHe + pN₂
pHe = P - pHe = 8.34 atm - 3.05 atm = 5.29 atm
where,
- P is the total pressure.
- pHe is the partial pressure of He.
- pN₂ is the partial pressure of N₂.
A mixture of 3.05-atm N₂(g) and 5.29-atm He(g) exerts a total pressure of 8.34 atm.
Learn more about Dalton's law here: brainly.com/question/14119417