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3 years ago

Can someone help me please

Mathematics

1 answer:

Anon25 [30]3 years ago

3 0

Answer:

$y = - \frac{2}{3} x + 7$

You get this equation when you plug in the values to find out the y intercept.

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Complete the set of ordered pairs for the relation.

neonofarm [45]

The set of ordered pairs is:

{(-2, 2), (-1, 0), (0, 2), (1, 4), (2, 6)}

<h3>How to complete the set of ordered pairs?</h3>

Here we have the relation:

y = 2*|x + 1|

And the domain is x ∈ { -2, -1, 0, 1, 2}

Evaluating in the values of the domain, we get:

if x = -2.

y = 2*|-2 + 1| = 2

Then we have the ordered pair (-2, 2)

if x = -1

y = 2*|-1 + 1| = 0

Then we have the ordered pair (-1, 0)

if x = 0

y = 2*|0 + 1| = 2

Then we have the ordered pair (0, 2)

if x = 1

y = 2*|1 + 1| = 4

Then we have the ordered pair (1, 4)

if x = 2

y = 2*|2 + 1| = 6

Then we have the ordered pair (2, 6)

The set of ordered pairs is:

{(-2, 2), (-1, 0), (0, 2), (1, 4), (2, 6)}

If you want to learn more about ordered pairs:

brainly.com/question/1528681

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2 years ago

What is the 10th term in the pattern with the formula 5n + 100?

yanalaym [24]

Easy
first term is n=1
so 10th term is n=10

5(10)+100=50+100=150

150 is 10th term

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4 years ago

I need to know the answer to the question with the circle

KATRIN_1 [288]

___________________________

◆ AREA RELATED TO CIRCLES ◆ ___________________________

As shown in the figure ,

Radius of circle = 5 cm

Side of square = 2 × (Radius of inscribed circle)

Side of square = 2 × 5 cm

Side of square = 10 cm = a

___________________________

Now ,
Area of shaded region = (Area of square) - ( Area of inscribed circle )

Area of shaded region =
${a}^{2} - \pi {r}^{2}$

Area of shaded region =
${10}^{2} - \frac{22}{7} \times {5}^{2}$

Area of shaded region = 100 - 78.571

$= 21.428 \: ans.$

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3 years ago

Problem Solve for t.<br> 2(t+1) = 10

Svetllana [295]

t=4

explanation

2(t+1)=10

2t+2=10

2t=8

t=4

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3 years ago

What is two and one-fourth subtracted by one-eighth?

Illusion [34]

Two and one eighth is the answer

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3 years ago