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krok68 [10]
3 years ago
14

The florist charges $31.75 for eight roses and five carnations. For one rose and three carnations, it cost $5.75. What is the co

st for a carnation?
Mathematics
1 answer:
Sedbober [7]3 years ago
5 0

Cost for a carnation is $0.75

Step-by-step explanation:

Let,

Rose = x

Carnation = y

According to given statement;

8x+5y=31.75   Eqn 1

x+3y=5.75   Eqn 2

Multiplying\ Eqn\ 2\ by\ 8\\8(x+3y=5.75)\\8x+24y=46 \ \ \ Eqn\ 3\\Subtracting\ Eqn\ 1\ from\ Eqn\ 3\\(8x+24y)-(8x+5y)=46-31.75\\8x+24y-8x-5y=14.25\\19y=14.25\\Dividing\ both\ sides\ by\ 19\\\frac{19y}{19}=\frac{14.25}{19}\\y=0.75

Cost for a carnation is $0.75

Keywords: Linear equations, Addition

Learn more about linear equations at:

  • brainly.com/question/10081622
  • brainly.com/question/10341324

#LearnwithBrainly

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Softa [21]

Answer:

(2)(120)(80) + (2)(120)(50) - (4)(60)(5²)

Step-by-step explanation:

The lateral faces of the building are the 4 sides of the building consisting:

2 rectangles of 120 ft by 80 ft

Area of the two rectangular faces = (2)(120)(80)

And

2 rectangles of 120 ft by 50 ft

Area of the two rectangular faces = (2)(120)(50)

✔️Total lateral surface area of the building = (2)(120)(80) + (2)(120)(50)

Note: we are asked to find the expression that represents the total surface area that needs to be painted given that there are 60 windows on each lateral face of the building of the shape of a square with side lengths of 5 ft.

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✅total lateral surface area of the building that will be painted = (2)(120)(80) + (2)(120)(50) - (4)(60)(5²)

6 0
2 years ago
Find csc 0, sin 0, and cot 0, where is the angle shown in the figure. Give exact values, not decimals approximations. (LISTING B
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Answer:

sup

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4 0
3 years ago
What is the side length of a cube with volume 343 in squared?
Thepotemich [5.8K]
Hi there!

The formula for a square is V = s^3. Using this formula, we can plug in the volume and solve for s.

WORK:
343 = s^3
s = 7

ANSWER:
The side length of a cube with volume 343 is 7 inches.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
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4 0
2 years ago
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