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3 years ago

Select all the correct answers. Which statements are true about function g? NO LINKS!!!

Mathematics

1 answer:

Anna35 [415]3 years ago

3 0

Answer:

A, B, E

Step-by-step explanation:

The attachment shows a graph of the function. It tends to infinity for x going to infinity in either direction. (A, B are true)

The right-side piece is cubic, not quadratic.

The U-shape tells you the function is decreasing on the left side.

The two function definitions have the same value at x=2, so the function has no discontinuities. It is continuous. (E is true)

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PLS HELP ME ILL MARK BRAINLIST IF SOMEONE CAN HELP ME WITH THESE 2 QUESTIONS!!

Nat2105 [25]

Answer:

1. Andrew grew 4 5/12 inches in 2 years

2. Abbey rode her bike for 3 3/8 hours in 2 days.

Step-by-step explanation:

When adding fractions you must have a common denominator for both of them.

First make the mixed fraction, improper fractions.

1 3/4 = 7/4

2 2/3 = 8/3

7/4 x 3/3 = 21/12

8/3 x 4/4 = 32/12

21 + 32 = 53

53/12 = 4 5/12

1 3/4 = 7/4

1 5/8 = 13/8

7/4 x 4/4 = 28/16

13/8 x 2/2 = 26/16

26 + 28 = 54

54/16 = 3 3/8

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3 years ago

The LA Dodgers hit the most homeruns in 2014. The number of homeruns accounted for 6% of the entire Major league baseball homeru

Lostsunrise [7]

For this one you need to find 6% of 583, which is the same as multiplying 583 times 0.06 which would give you a total of 34.98 which would be rounded to 35 since it's the closest one. So the LA Dodgers made 35 homeruns.
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3 years ago

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What number am i i have 11 hundreds,4tens,8ones,6 tenths and1hundredths

frozen [14]

The number you would have is 1148.61

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3 years ago

Given the conditional statement ~p -> q which statement is logically equivalent?

icang [17]

Any implication is logically equivalent to its contrapositive. In other words,

¬p ⇒ q ⇔ ¬q ⇒ p

(¬ means the same thing as ~, "not")

To prove this: recall that

p ⇒ q ⇔ ¬p ∨ q

This is because p ⇒ q is true if p is false, or both p and q are true, i.e.

p ⇒ q ⇔ ¬p ∨ (p ∧ q)

Disjunction (∨ or "or") distributes over conjunction (∧ or "and"), so that

p ⇒ q ⇔ (¬p ∨ p) ∧ (¬p ∨ q)

but ¬p ∨ p is always true, or a tautology, so we're just left with ¬p ∨ q.

Then

¬p ⇒ q ⇔ p ∨ q

… ⇔ q ∨ p

… ⇔ ¬(¬q) ∨ p

… ⇔ ¬q ⇒ p

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3 years ago

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Veseljchak [2.6K]

25 is the biggest number

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Select all the correct answers. Which statements are true about function g? NO LINKS!!!​

Select all the correct answers. Which statements are true about function g? NO LINKS!!!