Find the median of each set of data. 12, 8, 6, 4, 10, 1

Mathematics

2 answers:

Phantasy [73]2 years ago

7 0

Answer:

(6+8)/2 = 7

i really hope this helps!!!!!!!!!!!!!!!!!!!!!!!!!

Ray Of Light [21]2 years ago

6 0

Answer:

(6+8)/2 = 7

Step-by-step explanation:

You might be interested in

What is 12(6+9m) simplified

Alex

Answer:

12(6+9m)

therefore we multiple the 12 by the numbers in the blaket

72+10m

that's the correct answer

5 0

2 years ago

Read 2 more answers

Estimate the integral ∫6,0 x^2dx by the midpoint estimate, n = 6

Anettt [7]

Splitting up the interval [0, 6] into 6 subintervals means we have

$[0,1]\cup[1,2]\cup[2,3]\cup\cdots\cup[5,6]$

and the respective midpoints are $\dfrac12,\dfrac32,\dfrac52,\ldots,\dfrac{11}2$ . We can write these sequentially as ${x_i}^*=\dfrac{2i+1}2$ where $0\le i\le5$ .

So the integral is approximately

$\displaystyle\int_0^6x^2\,\mathrm dx\approx\sum_{i=0}^5({x_i}^*)^2\Delta x_i=\frac{6-0}6\sum_{i=0}^5({x_i}^*)^2=\sum_{i=0}^5\left(\frac{2i+1}2\right)^2$

Recall that

$\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6$
$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$
$\displaystyle\sum_{i=1}^n1=n$

so our sum becomes

$\displaystyle\sum_{i=0}^5\left(\frac{2i+1}2\right)^2=\sum_{i=0}^5\left(i^2+i+\frac14\right)$
$=\displaystyle\frac{5(6)(11)}6+\frac{5(6)}2+\frac54=\frac{143}2$

8 0

2 years ago

Any help on this please ?

dlinn [17]

Answer:

(0,-5), I believe.

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Please please please help.

saul85 [17]