F(x) = a(x-h)²<span> + k
</span><span><u>Given that the vertex is (-3 -6):</u>
</span>f(x) = a(x + 3)² -6
<span>
<u>Given that it passes through (0.0), find a:</u>
a(0 + 3)</span>² - 6 = 0
<span>
9a - 6 = 0
9a = 6
a = 6/9 =2/3
<u>So the equation is :</u>
</span>f(x) = 2/3(x + 3)² -6
<span>
<u>Write the equation in standard form:</u>
</span>f(x) = 2/3(x² + 6x + 9) - 6
f(x) = 2/3x² + 4x + 6 - 6
f(x) = 2/3x² + 4x
<span>
Answer: </span>f(x) = 2/3x² + 4x<span>
</span>
Answer:
The percentage change is 7.67%
Step-by-step explanation:
Cost of stock in a restaurant when bought= $300
Cost of stock in a restaurant now = $323
Change in cost = 323 -300 = $23
The percentage change is = (change in cost/Cost of stock in a restaurant when bought) * 100
The percentage change is = (23/300) * 100 = 7.67 %
The percentage change is 7.67%
Answer:
A sample is a subset of a population.
Step-by-step explanation:
Hello!
What you would need to do first is distribute the numbers inside the parenthesis.
6(t - 3) = 2(9 - 2t)
6t - 18 = 18 - 4t
Now that they've been distributed, you need to move all variables to one side, preferably to the left as it would make it easier to read and t would be positive.
6t - 18 = 18 - 4t
10t = 36
All that is left is to divide by 10 in order to leave t alone.
t = 3.6 or 18/5
Hello : let : y = f(x) so : y' = f'(x)
calculate : f'(x) and : f'(-1) given f(-1) = 2
by derivate : <span>4x3+2y2−11=4xy−x
12x² +4yy' = 4y +4xy' - 1
4yy' - 4xy' = - 12x² +4y -1
y' ( 4y - 4x) = 4y -12x² -1 ...(*)
if x = -1 y = 2 subsct in : (*)
y' (4(2)-4(-1)) = 4(2)-12(-1)² - 1
2y' = - 9
y' = - 9/2 = f'(- 1) ( the slope of the tangent )
</span>of the tangent line to the curve <span>at the point (−1,2) is :
y - 2 = (-9/2)(x +1)</span>
