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Genrish500 [490]
4 years ago
10

Find an equation for the line that passes through the point (-3, 6), parallel to the line through the points (0,-7) and (4,-15).

Write your answer in point-slope form.
Mathematics
1 answer:
Vitek1552 [10]4 years ago
8 0
Broken down into steps:

1.  Find the slope of the line segment that connecs the points (0,-7) and (4,-15).

2.  Start with the point-slope formula for the equation of a straight line:

y-b = m(x-a), where the given point is (a,b).  Borrow the value of m that you calculated in (1), above, and insert it into this point-slope formula.
Finish up by subst. the x- and y-values in (-3,6) into this formula.

Done!

You could, of course, solve this result for y if you wished.
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Answers:

A ' = (-2, -3)

B ' = (0, -3)

C ' = (-1, 1)

=======================================================

Explanation:

To apply an x axis reflection, we simply change the sign of the y coordinate from positive to negative, or vice versa. The x coordinate stays as is.

Algebraically, the reflection rule used can be written as (x,y) \to (x,-y)

Applying this rule to the three given points will mean....

  • Point A = (-2, 3) becomes A ' = (-2, -3)
  • Point B = (0, 3) becomes B ' = (0, -3)
  • Point C = (-1, -1) becomes C ' = (-1, 1)

The diagram is provided below.

Side note: Any points on the x axis will stay where they are. That isn't the case here, but its for any future problem where it may come up. This only applies to x axis reflections.

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