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3 years ago

How many integers from 4 to 50 inclusive are neither multiples of 3 nor 4????

Mathematics

1 answer:

puteri [66]3 years ago

6 0

Answer:

24 integers

Step-by-step explanation:

There are (50 - 4)+1 = 47 integers from 4 to 50 INCLUSIVE.

We find the multiples of 3 and find the multiples of 4 and subtract that from the 47 integers to get INTEGERS that are NEITHER multiple of 3 nor 4.

Let's list multiples of 3 (from 4 to 50 inclusive):

6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48

Multiples of 4 (from 4 to 40 inclusive):

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48

From the 2 lists, let's take out the <em>common ones:</em>

<em>THe common ones are 12, 24, 36, 48</em>

<em />

We count all from multiples of 3 list, but don't count the common from multiples of 4's list.

So there are 15 multiples of 3, and 8 multiples of 4

In total 15 + 8 = 23 multiples of 3 and 4

So there are 47 - 23 = 24 integers that are NOT multiples of 3 nor 4

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Look at the image. (calculus)

mash [69]

<h3>Answer: Choice H) 2</h3>

=============================================

Explanation:

Recall that the pythagorean trig identity is $\sin^2 x + \cos^2x = 1$

If we were to isolate sine, then,

$\sin^2 x + \cos^2x = 1\\\\\sin^2 x = 1-\cos^2x\\\\\sin x = \sqrt{1-\cos^2x}\\\\$

We don't have to worry about the plus minus because sine is positive when 0 < x < pi/2.

Through similar calculations, $\cos x = \sqrt{1-\sin^2x}\\\\$

Cosine is also positive in this quadrant.

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So,

$\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}\\\\\frac{\sin x}{\sin x}+\frac{\cos x}{\cos x}\\\\1+1\\\\2$

Therefore,

$\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}=2$

is an identity as long as 0 < x < pi/2

5 0

2 years ago

Read 2 more answers

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

olchik [2.2K]

Answer:

14.52 seconds.

Step-by-step explanation:

We have been given that the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation $y=-16x^2+224x+121$ . We are asked to find the time, when the rocket will hit the ground.

We know that the rocket will hit the ground, when height will be 0. So to find the time when rocket will hit the ground, we will substitute $y=0$ in our given equation as: