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Hunter-Best [27]
3 years ago
14

How many integers from 4 to 50 inclusive are neither multiples of 3 nor 4????

Mathematics
1 answer:
puteri [66]3 years ago
6 0

Answer:

24 integers

Step-by-step explanation:

There are (50 - 4)+1 = 47 integers from 4 to 50 INCLUSIVE.

We find the multiples of 3 and find the multiples of 4 and subtract that from the 47 integers to get INTEGERS that are NEITHER multiple of 3 nor 4.

Let's list multiples of 3 (from 4 to 50 inclusive):

6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48

Multiples of 4 (from 4 to 40 inclusive):

4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48

From the 2 lists, let's take out the <em>common ones:</em>

<em>THe common ones are 12, 24, 36, 48</em>

<em />

We count all from multiples of 3 list, but don't count the common from multiples of 4's list.

So there are 15 multiples of 3, and 8 multiples of 4

In total 15 + 8 = 23 multiples of 3 and 4

So there are 47 - 23 = 24 integers that are NOT multiples of 3 nor 4

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Artyom0805 [142]

The equation which shows the situation are 8g + 6h = 62 and 5g + 10h = 70.

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division.

Given that:-

  • Kyle and Lauren teach swimming lessons during the summer. Kyle has 8 classes with g students in each class and 6 classes with h students in each class.
  • Lauren has 5 classes with g students in each class and 10 classes with h students in each class.
  • If Kyle has a total of 62 students and Lauren has a total of 70 students,

The equation made by the given situation is:-

For kyle, there are g students attending 8 classes sp total number of students will be 8g similarly for h students there are 6 classes so the total number of h students will be 6h. The total number of students for both g and h students attending kyle's class is 62. So the equation will be given as:-

8g   +  6h  =  62

Now for Lauren, there are g students attending 5 classes so the total number of students will be 5g similarly for h students there are 10 classes so the total number of h students will be 10h. The total number of students for both g and h students attending Lauren's class is 70. So the equation will be given as:-

5g  +  10h  =  70

Therefore the equation which shows the situation are 8g + 6h = 62 and 5g + 10h = 70.

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3 0
2 years ago
Hailey wants to put a skirt around her desk to hide all her computer equipment and cords. She measured her desk, found the dimen
xeze [42]

Answer:

C.\ Perimeter = 48 * 18

Step-by-step explanation:

Given

See attachment for her sketch

Required

Which equation do not represent the perimeter

From the attached sketch:

L =18in --- Length

W =48in --- Width

Perimeter (P) is calculated as:

P = 2 * (L + W)

This gives:

P = 2 * (18 + 48) ---- This represents (A)

Open bracket

P = 2 * 18 + 2*48 ---- This represents (B)

In algebra:

2 * a means a+ a

So, the expression becomes

P = 18 + 18 +48 + 48 --- This represents (D)

<em>This implies that (C) does not represent the perimeter</em>

4 0
2 years ago
The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard dev
Vladimir [108]

Answer:

Probability that the average length of a sheet is between 30.25 and 30.35 inches long is 0.0214 .

Step-by-step explanation:

We are given that the population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.05 inches and a standard deviation of 0.2 inches.

Also, a sample of four metal sheets is randomly selected from a batch.

Let X bar = Average length of a sheet

The z score probability distribution for average length is given by;

                Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean = 30.05 inches

           \sigma   = standard deviation = 0.2 inches

             n = sample of sheets = 4

So, Probability that average length of a sheet is between 30.25 and 30.35 inches long is given by = P(30.25 inches < X bar < 30.35 inches)

P(30.25 inches < X bar < 30.35 inches)  = P(X bar < 30.35) - P(X bar <= 30.25)

P(X bar < 30.35) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{30.35-30.05}{\frac{0.2}{\sqrt{4} } } ) = P(Z < 3) = 0.99865

 P(X bar <= 30.25) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } <= \frac{30.25-30.05}{\frac{0.2}{\sqrt{4} } } ) = P(Z <= 2) = 0.97725

Therefore, P(30.25 inches < X bar < 30.35 inches)  = 0.99865 - 0.97725

                                                                                       = 0.0214

                                       

7 0
3 years ago
Write a number with a 8 in the hundredths place
boyakko [2]
201.08 

I think that would work.
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3 years ago
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The age of father is 4nyears.If the age of his daughter is(2n-9)years.find their total age.​
8_murik_8 [283]

Answer:

4n+(2n-9)

4n+2n-9

6n-9 =the total age

6n=9

divide by 6 both sides.

n=9/6

n=1.5 years.

substitute the value of n in the age of the father and the daughter.

Age of father=4×1.5

6years.

Age of Daughter = (2×1.5)-9

3-9

=-6 years

Total age

6-6=0

4 0
3 years ago
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