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Goryan [66]
3 years ago
9

Which ordered pair makes both inequalities true?

Mathematics
1 answer:
kvasek [131]3 years ago
6 0

Answer:

(3, 0)

Step-by-step explanation:

Given the inequality y > -2x + 3 and y ≤ x - 2

The graph of the inequalities are plotted using the geogebra graphing online calculator.

The portion of the graph that is shaded with dark blue, represents the portion that supports the equation.

All the ordered pair points given in the question are also labelled in the graph.

From the graph we can see that only point (3, 0) falls in the area that supports the equation. Hence (3, 0) makes both inequalities true.

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For the equation 2(4+x)+(13+x)=3x+k which value of k will create an equation with no solutions. .A. x B. 3x .C 15 D. 21
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<h3>Answer: choice C) 15</h3>

Simplify the left side to get

2(4+x)+(13+x)

2(4)+2(x) +13+x

8+2x+13+x

3x+21

------------

So the original equation

2(4+x)+(13+x) = 3x+k

turns into

3x+21 = 3x+k

------------

Subtract 3x from both sides

3x+21 = 3x+k

3x+21-3x = 3x+k-3x

21 = k

k = 21

-----------

If k = 21, then the original equation will have infinitely many solutions. This is because we will end up with 3x+21 on both sides, leading to 0 = 0 after getting everything to one side. This is a true equation no matter what x happens to be.

If k is some fixed number other than 21, then there will be no solutions. This equation is inconsistent (one side says one thing, the other side says something different). If k = 15, then

3x+21 = 3x+k

3x+21 = 3x+15

21 = 15 .... subtract 3x from both sides

The last equation is false, so there are no solutions here.

note: if you replace k with a variable term, then there will be exactly one solution.

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