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3 years ago

Which ordered pair makes both inequalities true?

Mathematics

1 answer:

kvasek [131]3 years ago

6 0

Answer:

(3, 0)

Step-by-step explanation:

Given the inequality y > -2x + 3 and y ≤ x - 2

The graph of the inequalities are plotted using the geogebra graphing online calculator.

The portion of the graph that is shaded with dark blue, represents the portion that supports the equation.

All the ordered pair points given in the question are also labelled in the graph.

From the graph we can see that only point (3, 0) falls in the area that supports the equation. Hence (3, 0) makes both inequalities true.

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The radius of the earth is 6378.1 km what is circumfrence of the earth in metres in standard form how many times can light encir

AVprozaik [17]

Answer:

Two things we need to remember:

Speed of light = c = 299,792,458 m / s

This means that the light in one second covers a distance of 299,792,458 m

And for a circle of radius R, the is:

C = 2*pi*R

where:

pi = 3.14

Then if the radius of the earth is 6,378.1 km, then the of the earth is:

C = 2*(3.14)*6,378.1 km = 40,054.468 km

And we know that 1 km = 1000m

Then the circumference of the earth is:

C = (40,054.468*1000) m = 40,054,468 m

Now we need to see how many times the light can encircle the earth per second. (we assume that the light can move in a circular path, this is not really accurate to the reality)

We know that in one second the light can cover a distance of: 299,792,458 m

And the circumference of the earth is: 40,054,468 m

The quotient between these two distances is the number of times that the light can encircle the earth:

N = (299,792,458 m)/(40,054,468 m) = 7.5

So light could encircle the earth 7.5 times per second.

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In an effort to make childrenâs toys safer and more tamperproof, toy packaging has become cumbersome for parents to remove in ma

Monica [59]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Old design samples(n1) = 220

New design samples (n2) = 220

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Null hypothesis : p1 - p2 ≥ 0.05

Alternative hypothesis : p1 - p2 < 0.05

Using the test statistic formula :

t = (P1 - P2) / √[P(1-P)(1/n1 + 1/n2)]

P = (81 + 41)/(220 + 220) = 122/440 = 0.277

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P value from z test at α = 0.05

P value = 0.00002

Test for significance at α = 0.01 ;

Test for significance at α = 0.1

Result is significant at both α levels, hence reject the Null.

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4 years ago

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leonid [27]

m∠C = 31

m∠D = 83

M∠E = 66

Hope this is helpful!

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