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-Dominant- [34]
3 years ago
6

Writing an equation and drawing its graph to model a real-world situation: Advanced

Mathematics
1 answer:
Leokris [45]3 years ago
3 0
Assuming that rent will always be constant.
C= 250×S+ 7500 for S>0
You might be interested in
Factorise x squared + 3x + 2​
Zielflug [23.3K]

Answer:

(x + 2)(x + 1)

Step-by-step explanation:

by factorising ;

=》

{x}^{2}  + 3x  + 2

=》

{x}^{2}  + 2x + x + 2

=》

x(x + 2) + 1(x + 2)

=》

(x + 2)(x + 1)

<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

8 0
3 years ago
Based on Pythagorean identities, which equation is true? A. Sin^2 theta -1= cos^2 theta B. Sec^2 theta-tan^2 theta= -1 C. -cos^2
Arturiano [62]

Answer:

D

Step-by-step explanation:

our basic Pythagorean identity is cos²(x) + sin²(x) = 1

we can derive the 2 other using the listed above.

1. (cos²(x) + sin²(x))/cos²(x) = 1/cos²(x)

1 + tan²(x) = sec²(x)

2.(cos²(x) + sin²(x))/sin²(x) = 1/sin²(x)

cot²(x) + 1 = csc²(x)

A. sin^2 theta -1= cos^2 theta

this is false

cos²(x) + sin²(x) = 1

isolating cos²(x)

cos²(x) = 1-sin²(x), not equal to sin²(x)-1

B. Sec^2 theta-tan^2 theta= -1

1 + tan²(x) = sec²(x)

sec²(x)-tan(x) = 1, not -1

false

C. -cos^2 theta-1= sin^2

cos²(x) + sin²(x) = 1

sin²(x) = 1-cos²(x), our 1 is positive not negative, so false

D. Cot^2 theta - csc^2 theta=-1

cot²(x) + 1 = csc²(x)

isolating 1

1 = csc²(x) - cot²(x)

multiplying both sides by -1

-1 = cot²(x) - csc²(x)

TRUE

3 0
3 years ago
I have 4 factors. Three of my factors are 1, 2, and 6. What is my fourth factor?
SIZIF [17.4K]

The 4th factor would be 3. You would find this out through a factor tree. If you don't know the original number when you start you look at your numbers. A factor of 1 usually goes with the highest number, assuming that the number 6 is the highest factor, that would be the original number. As 2 is the other known factor than we know that 3 has to be the last factor, because 2 x 3 = 6. It cannot be the number 12 because then there would be 6 factors not the needed 4.

7 0
3 years ago
A cab company charges $0.80 per mile plus $2 for tolls. Melissa has at most $16 to spend on her cab fare. Write and solve an ine
Anna35 [415]

Answer:

The maximum distance is 17.5 miles

No she can't make to the airport.

Step-by-step explanation:

Given the cab charges $0.8 per mile and $2 for tolls.

let the miles travelled by melissa be x.

The total charge is $(0.8*x+2)

Now given that she can spend a maximum of $16

so the inequality is

0.8*x+2\leq 16

0.8*x\leq 14

x\leq \frac{14}{0.8}

x\leq 17.5

Therefore the maximum distance she can travel is 17.5 miles

Since the distance to airport is 25 miles which is greater than 17.5 miles she cannot afford the cab.

3 0
3 years ago
Write an exponential equation in the form y = abx whose graph passes through points (4, 8) and (6, 32).
Artist 52 [7]

Answer:

Option C.

Step-by-step explanation:

The general exponential equation is

y=ab^x

It is given that the graph of exponential function passes through points (4,8) and (6,32). It means the equation of exponential function must be satisfied by these points.

8=ab^4       ...(1)

32=ab^6       ...(2)

Divide equation (2) by equation (1).

\dfrac{32}{8}=\dfrac{ab^6}{ab^4}

4=b^2

Taking square root on both sides.

2=b

Put b=2 in (1).

8=a(2)^4

8=16a

\dfrac{8}{16}=a

0.5=a

Substitute a=0.5 and b=2 in the given general exponential equation.

y=0.5(2)^x

Therefore, the correct option is C.

8 0
3 years ago
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