We know that
if the y terms is squared so it opens left or right
Is a Horizontal Parabola, the equation is of the form
(y-k)²=4(p)(x-h)
vertex is (h,k)
and
p is distance from focus to vertex, also distance from vertex to directrix
if p>0, then it opens to the right and directrix is to the left of vertex
if p<0, then it opens to the left and directrix is to the right of vertex
so
(y-1)²=4(4)(x-(-3))
vertex is (-3,1)
4>0 so directrix is to left of vertex
left is in x direction
-3-4=-7
directrix is x=-7
the answer isx=-7
see the attached figure
Answer:
Option A is correct.
Step-by-step explanation:
Given equation is 3x + 4y + 6z = 12
We have to find ordered triplet which indicate where the plane cuts the x-axis.
To find x-coordinate where plane cuts the x-axis we put y and z equal to 0.
3x + 4 × 0 + 6 × 0 = 12
3x + 0 + 0 = 12
3x = 12
x = 4
So, the coordinate where it cuts x-axis is ( 4 , 0 , 0 )
Therefore, Option A is correct.
Answer:
multiplication property of equality
Step-by-step explanation:
Given:
A quadrilateral WXYZ has vertices W(3, −5), X(1, −3), Y(−1, −5), and Z(1,−7).
Rule of rotation is
.
To find:
The vertices after rotation.
Solution:
We know that,
means 90 degrees counterclockwise rotation around the origin.
So, the rule of rotation is defined as

Using this rule, we get




Therefore, the required vertices after rotation are W'(5,3), X'(3,1),Y'(5,-1) and Z'(7,1).