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creativ13 [48]
2 years ago
9

Find the unit rate

Mathematics
1 answer:
blsea [12.9K]2 years ago
4 0

Answer:

vvvvvvvv

Step-by-step explanation:

A.36

B.5

C.1.70

D.7

E.3.80

F.100

G.14

H.0.64

I.1.02

J.9

Basically you dived the two numbers for your awnser

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The equation of the parabola is (y-1)^2 = 16(x+3)
Mandarinka [93]
We know that 

if  the y terms is squared so it opens left or right

Is a Horizontal Parabola, the equation is of the form
(y-k)²=4(p)(x-h)
vertex is (h,k)
and
p is distance from focus to vertex, also distance from vertex to directrix
if p>0, then it opens to the right and directrix is to the left of vertex
if p<0, then it opens to the left and directrix is to the right of vertex

so
(y-1)²=4(4)(x-(-3))
vertex is (-3,1)
4>0 so directrix is to left of vertex
left is in x direction
-3-4=-7
directrix is x=-7

the answer is
x=-7

see the attached figure

5 0
3 years ago
Which of these ordered triples indicates where the plane cuts the x-axis for this equation? 3x + 4y + 6z = 12
Eduardwww [97]

Answer:

Option A is correct.

Step-by-step explanation:

Given equation is 3x + 4y + 6z = 12

We have to find ordered triplet which indicate where the plane cuts the x-axis.

To find x-coordinate where plane cuts the x-axis we put y and z equal to 0.

3x + 4 × 0 + 6 × 0 = 12

3x + 0 + 0 = 12

3x = 12

x = 4

So, the coordinate where  it cuts x-axis is ( 4 , 0 , 0 )

Therefore, Option A is correct.

8 0
3 years ago
Which property will Sarah use to solve 6x = 42?
grin007 [14]

Answer:

multiplication property of equality

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Which ordered pair is a solution of the system of equations shown in the graph below?
Ad libitum [116K]

Answer: A

Step-by-step explanation:

3 0
2 years ago
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A quadrilateral WXYZ has vertices W(3, −5), X(1, −3), Y(−1, −5), and Z(1,−7). What are the vertices of r(90, O)(WXYZ)?
VashaNatasha [74]

Given:

A quadrilateral WXYZ has vertices W(3, −5), X(1, −3), Y(−1, −5), and Z(1,−7).

Rule of rotation is r_{(90^\circ, O)}(WXYZ).

To find:

The vertices after rotation.

Solution:

We know that, r_{(90^\circ, O)}(WXYZ) means 90 degrees counterclockwise rotation around the origin.

So, the rule of rotation is defined as

(x,y)\to (-y,x)

Using this rule, we get

W(3,-5)\to W'(5,3)

X(1,-3)\to X'(3,1)

Y(-1,-5)\to Y'(5,-1)

Z(1,-7)\to Z'(7,1)

Therefore, the required vertices after rotation are W'(5,3), X'(3,1),Y'(5,-1) and Z'(7,1).

8 0
3 years ago
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