Question

Mass in grams of 6.25 mol of copper (II) nitrate?

Answer 1

Cu = 63.546
N= 14.001 g/mol
O= 15.999 g/mol * 3 = 47.997

Copper (II) Nitrate has a MW of 125.544 g/mol

6.25 x 125.544

= 784.65 <--- is your answer, if there were was a multiple choice or not :)

Answer 2

Answer:

Mass of 6.25 moles of copper(II) nitrate = 1025 grams

Explanation:

Let us calculate the molar mass of Copper (II) nitrate

Molecular formula = Ca(NO₃)₂

Atomic mass of Ca = 40 g/mol

Atomic mass of N =14 g/mol

Atomic mass of O = 16 g/mol

molar mass of Ca(NO₃)₂ = 40 + (14 X2) +( 6X16) = 164 g/mol

$moles=\frac{mass}{molarmass}$

therefore

mass = moles X molar mass

mass = 6.25 X 164 = 1025 grams