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nasty-shy [4]
3 years ago
13

Shortly after the 2014 AFC Championship game between the New England Patriots and the Indianapolis Colts, the Patriots were accu

sed of deflating the game balls in order to make them softer and easier to catch and throw. The Patriots claimed that any decrease in the pressure of the footballs was due to a decrease in temperature during the game. Is the Patriots’ claim scientifically valid?
A.
Yes, because as the temperature of a gas decreases, pressure increases.

B.
No, because as the temperature of a gas decreases, pressure increases.

C.
Yes, because as the temperature of a gas decreases, pressure decreases.

D.
No, because as the temperature of a gas decreases, pressure decreases.
Chemistry
2 answers:
Bogdan [553]3 years ago
8 0
D. Because as the Gas temp decreases the follows and decreases as well
asambeis [7]3 years ago
7 0

Answer:

Deflategate was a National Football League (NFL) controversy involving the allegation that New England Patriots quarterback Tom Brady ordered the deliberate deflation of footballs used in the Patriots' victory against the Indianapolis Colts in the 2014 American Football Conference (AFC) Championship Game.

Explanation:

Hope it helps you!!!

Pls mark me brainliest!!!

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WILL GIVE BRAINLIEST!!!
Rus_ich [418]

Answer:

The answer is B

Explanation:

The answer is B because representative particles can only be atoms.

3 0
3 years ago
Assuming that the solubility of radon in water with 1 atm pressure of the gas over the water at 30 ∘C is 7.27×10−3M, what is the
Daniel [21]

Answer:

K = 137.55 atm/M.

Explanation:

  • The relationship between gas pressure and the  concentration of dissolved gas is given by  Henry’s law:

<em>P = (K)(C)</em>

where P is the partial pressure of the gaseous  solute above the solution (P = 1.0 atm).

k is a constant (Henry’s constant).

C is the concentration of the dissolved gas (C = 7.27 x 10⁻³ M).

∴ K = P/C = (1.0 atm)/(7.27 x 10⁻³ M) = 137.55 atm/M.

4 0
3 years ago
Chlorine has two isotopes. The isotope with a mass of 34.969 amu has a relative abundance of 75.77%. The isotope with a mass of
Mars2501 [29]
34.969*.7577+36.966*.2433=35.489
5 0
3 years ago
Read 2 more answers
Calculate the cfse for a d^3 system in an octahedral field in units of ∆_o. In other words, do not enter "∆_o" with your answer.
Rudik [331]

Magnetic moment (spin only) of octahedral complex having CFSE=−0.8Δo and surrounded by weak field ligands can be : Q

To answer this, the Crystal Field Stabilization Energy has to be calculated for a (d3 metal in both configurations. The geometry with the greater stabilization will be the preferred geometry. So for tetrahedral d3, the Crystal Field Stabilization Energy is: CFSE = -0.8 x 4/9 Δo = -0.355 Δo.

[Co(CN)64-] is also an octahedral d7 complex but it contains CN-, a strong field ligand. Its orbital occupancy is (t2g)6(eg)1 and it therefore has one unpaired electron. In this case the CFSE is −(6)(25)ΔO+(1)(35)ΔO+P=−95ΔO+P.

The crystal field stabilization energy (CFSE) (in kJ/mol) for complex, [Ti(H2O)6]3+. According to CFT, the first absorption maximum is obtained at 20,3000cm−1 for the transition.

To learn more about crystal field stabilization energy  visit:brainly.com/question/29389010

#SPJ4

8 0
1 year ago
Imagine a small synthetic vesicle made from pure phospholipids enclosing an interior lumen containing 1 mM glucose and 1 mM sodi
Alexeev081 [22]

Answer:

C. H2O diffuses in.

Explanation:

<em>The phospholipids-made synthetic vesicle in this case will act like a semi-permeable membrane while the solution in the interior lumen will be hypertonic to the surrounding pure water. </em>

<em>Hence, water molecules will diffuse into the lumen through the semi-permeable membrane because of the osmotic gradient that exist between the internal and the surrounding solution of the vesicle.</em>

7 0
4 years ago
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