Answer:

Explanation:
By definition one <em>half-life</em> is the time to reduce the initial concentration to half.
For a <em>second order reaction </em>the rate law equations are:
![\dfrac{d[B]}{dt}=-k[B]^2](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%5BB%5D%7D%7Bdt%7D%3D-k%5BB%5D%5E2)
![\dfrac{1}{[B]}=\dfrac{1}{[B]_0}+kt](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B%5BB%5D%7D%3D%5Cdfrac%7B1%7D%7B%5BB%5D_0%7D%2Bkt)
The <em>half-life</em> equation is:
![t_{1/2}=\dfrac{1}{k[A]_0}](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D%5Cdfrac%7B1%7D%7Bk%5BA%5D_0%7D)
Thus, substitute the<em> rate constant</em>
and the <em>half-life </em>time <em>224s</em> to find [A]₀:
![224s=\dfrac{1}{1.30\times10^{-3}M^{-1}\cdot s^{-1}[A]_0}](https://tex.z-dn.net/?f=224s%3D%5Cdfrac%7B1%7D%7B1.30%5Ctimes10%5E%7B-3%7DM%5E%7B-1%7D%5Ccdot%20s%5E%7B-1%7D%5BA%5D_0%7D)
![[A]_o=0.291M](https://tex.z-dn.net/?f=%5BA%5D_o%3D0.291M)
If the volume of 425 grams was 48.0 cm³, simply divide
g/cm³ = 425 g/48 cm³ = 8.85 g/cm³
If using water in water displacement, 1 mL = 1 cm³
8.85 g/cm³ = 8.85 g/mL
This density is most closely aligned with that of B. Copper
Hope I helped!
If enought heat was removed by water, its will probably evaporate or turn into steam.
Answer : The number of moles of sulfur needed to oxidize will be, 3 moles
Solution : Given,
Moles of zinc = 3 moles
The balanced reaction will be,

By the stoichiometry, 1 mole of
ion react with the 1 mole of
to give 1 mole of zinc sulfide.
From the balanced reaction, we conclude that
As, 1 mole of zinc react with 1 mole of sulfur
So, 3 moles if zinc react with 3 moles of sulfur
Hence, the number of moles of sulfur needed to oxidize will be, 3 moles